Answer:
These three factors are required for ionization potential or ionization energy.
Explanation:
Ionization potential refers to the amount of energy which is required for the removal of outermost electron of the atom. If the atom size is big so the outermost electron is far from the nucleus and low energy is required for its removal due to lower force of attraction between nucleus and outermost electron. If the nuclear charge is higher, so the electron is tightly held by the nucleus and require more energy for its removal. Nuclear charge means number of protons present in the nucleus.
The electron configuration of alkali metals would then resemble those of group 17 of the periodic table in the compounds they form.
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What is periodic table?</h3>
Periodic table is defined as a tabular approach of showing the items so that they appear in the same vertical column or group when their attributes are similar. Phosphorus is the oldest chemical element, and hassium is the newest. Please take note that, unlike in the Periodic system, the elements do not exhibit their natural relationships with one another.
The elements that make up group 17 of the periodic table are the halogens. They are nonmetals that are reactive, such as iodine, bromine, chlorine, and fluorine. Halogens are non-metals that are very reactive. These substances share a lot of characteristics with one another.
Thus, the electron configuration of alkali metals would then resemble those of group 17 of the periodic table in the compounds they form.
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To learn more about periodic table, refer to the link below:
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Answer:
i think its d i may be wrong
Explanation:
You have to figure out a way to write the two unknown abundances in terms of one variable.
The total abundance is 1 (or 100%). So if you say the abundance for the first one is X then the abundance for the second one has to be 1-X (where X is the decimal of the percentage so say 0.8 for 80%).
203(X) + 205(1-X) = 204.4
Then you just solve for X to get the percentage for TI-203.
And then solve for 1-X to get the percentage for TI-205.
After that the higher percentage would be the most abundant.
203x + 205 - 205x = 204.4
-2x + 205 = 204.4
-2x = -0.6
x = 0.3
1-x = 0.7
Then the TI-205 would have the highest percentage and would be the most abundant.
Answer:
The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.