3 years ago

PLEASE HELP RN....i’m stuck

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

7 0

Answer:

612+c>=2000

Step-by-step explanation:

You might be interested in

Sam has 9 yellow pencils in his desk. Three fourths of his pencils are yellow How many pencils does Sam have in his desk

polet [3.4K]

Sam has 12 pencils in total.

7 0

4 years ago

Read 2 more answers

Write all the factors of 21 .<br> Use commas to separate them.

Advocard [28]

Answer:

1, 3, 7, 21!

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If 9/10 of cats prefer felix food of the total 500 surveyed,how many do NOT prefer felix

gregori [183]

Answer:

450 cats do NOT prefer felix

Step-by-step explanation:

9/10= x/500

6 0

3 years ago

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

3 years ago

There is a picture attached. that is the question

enot [183]

-2

explanation:

coefficient is the number in front of the term it's asking for. so the number in front of x² would be the -2.

another tip the b's represents x in that equation!!

7 0

3 years ago