All categories

3 years ago

How many moles of Cu do you need to react with 12 moles of O2? 2Cu(s) + O2(g) 2CuO(s)

Chemistry

1 answer:

zzz [600]3 years ago

3 0

Answer:

24 mol Cu

General Formulas and Concepts:

Chemistry

Stoichiometry

Explanation:

Step 1: Define

RxN: 2Cu (s) + O₂ (g) → 2CuO (s)

Given: 12 moles O₂

Step 2: Stoichiometry

$12 \ mol \ O_2(\frac{2 \ mol \ Cu}{1 \ mol \ O_2} )$ = 24 mol Cu

Step 3: Check

We are given 2 sig figs.

Our final answer is in 2 sig figs, so no need to round.

You might be interested in

Why do atoms share electrons in covalent bonds??

ra1l [238]

Atoms in covalent bonds do combine so as to be stable. As covalent bond consist non metals e.g O2 in this example each atom has vacance of 2 orbitals/ electrons so shairing electrons result their stability

6 0

3 years ago

Read 2 more answers

What is the orbital or electronic geometry of a molecule with 0 nonbonding electron pairs and 2 bonding electron pairs?

disa [49]

Linear is the answer

3 0

3 years ago

LOLZ PLZ HELP PLZZZZ

Kipish [7]

It smells so bad that no one or animal will get near it

5 0

3 years ago

A solution is prepared by dissolving 106.3 g HCl(g) in enough water to make 175.0 L of solution. The ph of this solution is

DedPeter [7]

Answer:

moles HCl = 101.2 g /36.461 g/mol=2.78

[H+]= 2.78 mol/ 150 L =0.0185

pH = - log 0.0185=1.73

1.73 is the answer

3 0

3 years ago

An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit

Anon25 [30]

Answer: The molar mass of unknown triprotic acid is 97.66 g/mol

Explanation:

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of triprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL$

Putting values in above equation, we get:

$3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol$

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0

3 years ago