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LuckyWell [14K]
3 years ago
14

How many moles of Cu do you need to react with 12 moles of O2? 2Cu(s) + O2(g) 2CuO(s)

Chemistry
1 answer:
zzz [600]3 years ago
3 0

Answer:

24 mol Cu

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry

Explanation:

<u>Step 1: Define</u>

RxN: 2Cu (s) + O₂ (g) → 2CuO (s)

Given: 12 moles O₂

<u>Step 2: Stoichiometry</u>

<u />12 \ mol \ O_2(\frac{2 \ mol \ Cu}{1 \ mol \ O_2} ) = 24 mol Cu

<u>Step 3: Check</u>

<em>We are given 2 sig figs.</em>

Our final answer is in 2 sig figs, so no need to round.

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3 years ago
What is the property of water, powdered drink mix, and sugar after mixing
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When all ingredients are mixed the 2 solids are dissolved into the water making it all liquid but the taste is still there. The drink mix gives it a little flavor and the sugar makes it sweet. The water is there to make it a liquid, it all turns out to be a colored liquid. Hope this helped! :)
7 0
3 years ago
Which is the strongest acid listed in the table?
andrew11 [14]

Answer:

Hydrofluoric acid.

Explanation:

To know which of the acid is the strongest, let us determine the pka of each acid. This is illustrated below:

1. Acetic acid

Ka = 1.8x10^-5

pKa =..?

pKa = –logKa

pKa = –Log 1.8x10^-5

pKa = 4.74

2. Benzoic acid

Ka = 6.5x10^-5

pKa =..?

pKa = –logKa

pKa = –Log 6.5x10^-5

pKa = 4.18

3. Hydrofluoric acid.

Ka = 6.8x10^-4

pKa =..?

pKa = –logKa

pKa = –Log 6.8x10^-4

pKa = 3.17

4. Hypochlorous acid

Ka = 3.0x10^-8

pKa =..?

pKa = –logKa

pKa = –Log 3.0x10^-8

pKa = 7.52

Note: the smaller the pKa value, the stronger the acid.

The pka of the various acids as calculated above is given below:

Acid >>>>>>>>>>>>>>>>>> pKa

1. Acetic acid >>>>>>>>>> 4.74

2. Benzoic acid >>>>>>>> 4.18

3. Hydrofluoric acid >>>> 3.17

4. Hypochlorous acid >> 7.52

From the above illustration, we can see that hydrofluoric acid has the lowest pKa value. Therefore, hydrofluoric acid is the strongest among them.

6 0
3 years ago
How many grams of methane gas (CH4) need to be combusted to produce 12.5 L water vapor at 301 K and 1.1 atm? Show all of the wor
tangare [24]
Answer is: 4.45 grams of methane gas <span>need to be combusted</span>.
Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
Ideal gas law: p·V = n·R·T.<span>
p = 1.1 atm.
T = 301 K.
V(H</span>₂O) <span>= 12.5 L.
R = 0,08206 L·atm/mol·K.
</span>n(H₂O) = <span>1.1 atm · 12.5 L ÷ 0,08206 L·atm/mol·K · 301 K.
</span>n(H₂O) = 0.556 mol.
From chemical reaction: n(H₂O) : n(CH₄) = 2 : 1.
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m(CH₄) = 0.278 mol · 16 g/mol.
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4 0
3 years ago
All molecules have the same kinetic energy and hence the same speed.<br><br> O True<br><br> O False
topjm [15]
False...their speed differs
4 0
2 years ago
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