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Kaylis [27]
3 years ago
6

What type of rock would be formed in this plant-rich swamp?

Chemistry
1 answer:
adell [148]3 years ago
7 0
We are asked to identify what type of rock would be formed in a plant-rich swamp. We all know that plant dies and the remain leaves in the soil called peat. Temperature, pressure and heat causes the remains to submerged under the soil bed layer and converts it into a waxy substance called kerogen. Kerogen then mixes with the rock under the soil bed layer to create what is called an oil shale. Oil shale is somehow similar to a coal. Both creates an energy when ignited. Therefore the correct answer to the question being asked is COAL or Oil Shale.
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Which equation correctly relates kinetic energy mass and velocity
jolli1 [7]

Answer: The equation for kinetic energy is \frac{1}{2}mv^2

Explanation:

Kinetic energy is the energy possessed by the virtue of object's motion. It is defined as the work needed to move a body of a given mass from rest to its velocity.

Mathematically,

K.E.=\frac{1}{2}mv^2

where,

m = mass of the body

v = velocity of the body.

Hence, above equation relates kinetic energy to the mass and velocity of the body.

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Which substance has Hf defined as 0 kJ/mol? H2O (s) Ne (l) O2 (g) CO2 (g)
vlabodo [156]

Answer:

O₂ (g).

Explanation:

  • All elements that found in nature has heat of formation (Hf) equal 0 J/mol.
  • So, the substance that  has heat of formation (Hf) equal 0 J/mol is O₂ (g).
  • H₂O is formed from the reaction of hydrogen and oxygen and has Hf, Also, the solidification of H₂O (s) from H₂O (l) has (Hf).
  • Although, Ne (g) is found in nature and has no Hf, the liquification to form Ne (l) has heat of formation (Hf).
  • CO₂ (g) is formed from the reaction between carbon and oxygen and so has heat of formation (Hf).
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3 years ago
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How do flowering plants depend on other living things in order to reproduce?
Rufina [12.5K]

Answer:

They depend on people to water them and make sure they are by a window for sunlight

Explanation:

plants cant do these things by themselves

5 0
3 years ago
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A 33.0−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h
Lostsunrise [7]

Answer:

THE SPECIFIC HEAT OF THE ALLOY IS 0.9765 J/g K

Explanation:

Mass of alloy = 33 g

Initial temperature of alloy = 93°C

Mass of water = 50 g

Initail temp. of water = 22 °C

Heat capacity of calorimeter = 9.20 J/K

Final temp. = 31.10 °C

specific heat of alloy = unknown

specific heat capacity of water = 4.2 J/g K

Heat = mass * specific heat * change in temperature = m c ΔT

Heat = heat capcity * chage in temperature = Δ H * ΔT

In calorimetry;

Heat lost by the alloy = Heat gained by water + Heat of the calorimeter

                     mc ΔT = mcΔT + Heat capacity * ΔT

33 * C * ( 93 - 31.10) = 50 * 4.2 * ( 31.10 -22) + 9.20 * ( 31.10 -22)

33 * C * 61.9 = 50 * 4.2 * 9.1 + 9.20 * 9.1

2042.7 C = 1911 + 83,72

C = 1911 + 83.72 / 2042.7

C = 1994.72 /2042.7

C =0.9765 J/g K

The specific heat of the alloy is 0.9765 J/ g K

5 0
3 years ago
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