The number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles
<h3>Stoichiometry </h3>
From the question, we are to determine the number of moles of silver oxide (I) needed to produce 4 moles of silver
First, we will write the balaced chemical equation for the decomposition of silver oxide (I)
2Ag₂O(s) → 4Ag(s) + O₂(g)
This means, 2 moles of silver oxide (I) [Ag₂O] decomposes to give 4 moles of <u>silver </u>and 1 mole of oxygen gas.
From the <em>balanced chemical equation</em>, it is easy to deduce the number of moles of silver oxide (I) that would give 4 moles of silver.
Hence, the number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles
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Answer:
(3S)-2-chloro-2,3-dimethylpentane is produced exclusively.
Explanation:
Electrophilic addition to (3S)-2,3-dimethylpent-1-ene proceeds through a carbocationic intermediate.
In the first step, 
adds onto double bond to produce more stable tertiary carbocation. (protonation)
In the second step, 
adds onto carbocation to produce (3S)-2-chloro-2,3-dimethylpentane exclusively.(nucleophilic addition)
So, option (d) is correct.
Answer:
Explanation:
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In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:
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Energy= 2381 joules
heat= Mass(kg) *change in temperature(K) * Cp
2381=0.155*(15)*Cp
Cp=1024 J/kg K
