The force that pulls objects toward each other

A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac

Sedbober [7]

Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

λ = wavelength = 5.5 m

Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

$v = f\lambda$

where,

v= speed of wave = ?

f = frequency of wave = $\frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz$

Therefore,

$v = (0.217\ Hz)(5.5\ m)\\$

5 0

3 years ago

A rope has a mass of 10.43 pounds per meter. Express this in milligrams per centimeter.

gregori [183]

Answer:

47347.1936 milligrams per centimeter

Explanation:

1 pound is equal 453592 milligrams.

one meter is 100cm

10.43*453952/100= 47347.1936milligrams per cm

3 0

4 years ago

Intensity: Radiation of a single frequency reaches the upper atmosphere of the earth with an intensity of 1350 W/m2. What is the

sesenic [268]

Answer:

The right answer is "1010 V/m".

Explanation:

The given values are:

Intensity,

$I=1350 \ W/m^2$

$c = 3.00\times 108 \ m/s$

$\mu_0= 4\pi\times 10^{-7} \ T.m/A$

Now,

The electric field's maximum value will be:

= $\sqrt{2\times u\times c\times I}$

On substituting the values in the above formula, we get

= $\sqrt{2\times 4\times \pi\times 10^{-7}\times 3\times 10^8\times 1350}$

= $\sqrt{32400\times 3.14\times 10^{-7}\times 10^8}$

= $1010 \ V/m$

3 0

3 years ago

Light of wavelength 519 nm passes through two slits. In the interference pattern on a screen 4.6 m away, adjacent bright fringes

Veseljchak [2.6K]

Answer:

The separation of the two slits is 0.456 mm.

Explanation:

Given the wavelength of light = 519 nm

The indifference pattern = 4.6 m

Adjacent bright fringes = 5.2 mm

In the interference, the equation required is Y = mLR/d

Here, d sin theta = mL

L = wavelgnth

For bright bands, m is the order = 1,2,3,4

For dark bands, m = 1.5, 2.5, 3.5, 4.5

R = Distance from slit to screen (The indifference pattern)

Y = Distance from central spot to the nth order fringe or fringe width

Thus, here d = mLR/Y

d = 1× 519nm × 4.6 / 5.2mm

d = 0.459 mm

3 0

4 years ago

How do i find minimum potential energy for a roller coaster

Elenna [48]

Don't know about the minimum part, but potential energy is calculated using the following formula:

$PE = 9.8 \frac{m}{s^2} * m * h$

You need to know the planet (or simply the gravity of the planet), the height of the roller coaster car, and the mass of the car.

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4 0

4 years ago