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3 years ago

Determine the energy associated with an e- in hydrogen at n=2 to n=4

Chemistry

1 answer:

jeka57 [31]3 years ago

6 0

Answer:

Kinetic energy of electron = -E₂ = 3.4 ev

Kinetic energy of electron = -E₄ = 0.85 ev

Explanation:

In case of hydrogen atom energy associated with nth state is,

En = -13.6/n²

For n = 2

E₂ = -13.6 / 2²

E₂ = -13.6/4

E₂ = -3.4 ev

Kinetic energy of electron = -E₂ = 3.4 ev

For n = 4

E₄ = -13.6 / 4²

E₄ = -13.6/16

E₄ = -0.85 ev

Kinetic energy of electron = -E₄ = 0.85 ev

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Olegator [25]

Answer:

An Arrhenius Base

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3 years ago

The average atomic mass of Eu is 151.96 amu. There are only two naturally occurring isotopes of europium, Eu with a mass of 151.

earnstyle [38]

Answer:

The percentage abundance of Eu isotopes are 52 % and 48 % .

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope,:

% = x %

Mass = 151.0 amu

For second isotope :

% = 100 - x

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Given, Average Mass = 151.96 amu

Thus,

$151.96=\frac{x}{100}\times {151.0}+\frac{100-x}{100}\times {153.0}$

Solving for x, we get that:

x = 52 %

<u>Thus percentage abundance of Eu isotopes are 52 % and 48 % .</u>

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3 years ago

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3 years ago

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A sample of black coffee was measured to have [h3o+] = 7.94 × 10−6. what is true about this solution?

Sveta_85 [38]

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To determine the pH of a solution, the negative log (-log) of the hydronium/hydrogen ion concentration (molarity) of the solution is calculated. Thus (assuming that the given hydrogen ion concentration is in molarity (mol/L)),

pH = -log( $H^{+}$ ) or -log( $H_{3} O^{+}$
pH = -log (<span>7.94 × 10−6 mol/L)
pH = 5.13

Because the pH is less than 7 (within the range 1 to 6), then the black coffee solution is acidic. </span>

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3 years ago

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Tcecarenko [31]

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