What is the molar mass of iron (III) oxide?

Chemistry

1 answer:

san4es73 [151]3 years ago

4 0

Answer:

159.69 g/mol

Explanation:

Here's the answer hope it helps

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Calculate the moles of camphor dissolved in 1.32 L of phenol. The molar mass of camphor is 152 g/mol and the molarity of phenol

LUCKY_DIMON [66]

Answer:

moles of camphor = 0.0522 moles

Explanation:

MW camphor= 152 g/mol

V solution = 1.32 L

M solution = 6.01 M

moles solute = ?

To calculate the moles of camphor, you must first know the grams of solute (camphor) that exist in the solution, this is calculated from the molarity equation:

$M=\frac{solute mass}{solution volume}$

From there the grams of the solute (camphor) are cleared:

$solutemass=M*solutionvolume=6.01M*1.32L=7.9332g$

Then by means of the molecular weight (MW) equation the moles can be obtained:

$MW=\frac{mass}{moles}$

$moles=\frac{mass}{MW} =\frac{7.9332g}{152\frac{g}{mol} } =0.0522 moles$

6 0

4 years ago

A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?

Oksana_A [137]

Hello!

To solve this problem we're going to use the Charles' Law. This Law describes the relationship between Volume and Temperature in an ideal gas. Applying this law we have the following equation:

$\frac{V1}{T1} = \frac{V2}{T2} \\ \\ T2= \frac{V2*T1}{V1}= \frac{235 mL * 105 ^{\circ}C }{455 mL}=54,23 ^{\circ}C$

So, the final temperature is 54,23 °C

Have a nice day!

5 0

4 years ago

Read 2 more answers

What is the volume of 6.40 grams of O₂ gas at STP?

gtnhenbr [62]

The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the following formula:

p = m/v

Where;