Answer:
moles of camphor = 0.0522 moles
Explanation:
<u>Data:</u>
MW camphor= 152 g/mol
V solution = 1.32 L
M solution = 6.01 M
moles solute = ?
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To calculate the moles of camphor, you must first know the grams of solute (camphor) that exist in the solution, this is calculated from the molarity equation:

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From there the grams of the solute (camphor) are cleared:

-
Then by means of the molecular weight (MW) equation the moles can be obtained:


Hello!
To solve this problem we're going to use the
Charles' Law. This Law describes the relationship between
Volume and Temperature in an ideal gas. Applying this law we have the following equation:

So, the final temperature is
54,23 °CHave a nice day!
The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the following formula:
p = m/v
Where;
- p = density
- m = mass
- v = volume
According to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.
1.43g/L = 6.4g/V
Volume of O2 = 6.4 ÷ 1.43 = 4.48L
Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.
Learn more about volume at: brainly.com/question/1578538
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The reaction is
CH3OH(l)→CH3OH(g)
To calculate ΔG°
ΔG°=ΔG°f of CH3OH(g)-ΔG°f of CH3OH(l)
=162.3kJ/mol - (-166.6kJ/mol
=4.3kJ/mol.
Answer:
no work was needed. Blinking does not require using energy sometimes we blink without thinking.
Explanation: