W=0.360
p=1.18g/mL
pH=2.12
v=14.0 L
M(HCl)=36.46 g/mol
v₀-?
1) pH=-lg[H⁺]
[H⁺]=c(HCl)=10^(-pH)
n(HCl)=v[H⁺]=v*10^(-pH)
2) n(HCl)=m(HCl)/M(HCl)=wv₀p/M(HCl)
3) v*10^(-pH)=wv₀p/M(HCl)
v₀=v*10^(-pH)M(HCl)/(wp)
v₀=14.0*10^(2.12)*36.46/(0.360*1.18)=9.115 mL
Approximately 9.1 mL of concentrated solution required.
Answer:
The mass of water is 36 g.
Explanation:
Mass of hydrogen = 4 g
Mass of water = ?
Solution:
First of all we will write the balance chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen = mass / molar mass
Number of moles of hydrogen = 4 g/ 2 g/mol
Number of moles of hydrogen = 2 mol
Now we compare the moles of water with hydrogen from balance chemical equation.
H₂ : H₂O
2 : 2
Mass of water = moles × molar mass
Mass of water = 2 mol × 18 g/mol
Mass of water = 36 g
If the water oxygen is in excess than mass of water would be 36 g.
Answer:
A. An atom
Explanation:
A large scale model is one that is bigger than the object itself. These are needed to visualise structures and behaviours that we cannot normally see. A large scale model is needed for small objects, such as an atom. Larger objects do not need<em> even bigger</em> models
Answer:
The answer is the second picture.
Explanation:
Answer:
21g
Explanation:
no.ofmol fe2o3=39.5/(56×2+16×3)=0.25mol
from equation 1mole fe2o3 react with 3mole co
so,0.25mol fe2o3 react with 0.75mol co
mass of co=0.75×(12+16)=21g
