Answer:
Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution
Explanation:
As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.
When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.
This gas turn red litmus paper blue.
This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).
If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.
<span>You can find
the number of moles in equilibrium if you got the chemical reaction correctly. Make
sure that you got the exact chemical formula of the substance that is reacting
and the yielded product. If you got them, balance the chemical reaction. If the
chemical reaction is balanced, the system is in equilibrium. You can find the
number of moles in equilibrium at the coefficients of the chemical substances
you are balancing. For example, N2 + 3H2 -> 2NH3. The number of moles of N2
is 1, H2 is 3 and NH3 is 2.</span>
The question is incomplete. Complete question is
<span>In an aqueus solution, which substance yields hydrogen ions as the only positive ions in the solution? 1)NaH 2)HCOOH 3)LiOH 4) CH3CH2OH?
.............................................................................................................................
Answer: Correct answer is option 2, HCOOH
Reason:
HCOOH is a formic acid. When mixed in water, it undergoes dissociation which can be represented as
HCOOH </span>↔ HCOO- + H+
The compound NaH, will generate hydride ion (H-), while LiOH is an ionic compound, hence when dissolved in water it generated OH- ions. The compound CH3CH2OH is named as ethyl alcohol. This compound donot dissociate in aqueous medium.
<span>n= PV/RT </span>
<span>n= 0.44x0.025/0.082x297.5 </span>
<span>n=0.000450913 </span>
<span>22.4L/1 mole = y L/ 0.000450913 </span>
<span>y=0.0101043 L </span>
<span>y = 10.1 mL</span>
