Answer:
When the two gases are mixed, the ammonium chloride precipitates in the tube walls.
Explanation:
This is the reaction:
HCl (g) + NH₃(g) → NH₄Cl (s) ↓
As the product formed is solid at room temperature, a suspension is first formed in the internal air of the tube that appears as a cloud. Afterwards it finally precipitates into the walls forming a white layer
Answer:
The cooler water is denser
Explanation:
Convection drives the boiling of water placed on a stove in a kettle.
During convection, heat is circulated by density differences in portions of a fluid.
Convection is a form of heat transfer in fluids especially gas and liquid.
- In boiling water, the heat is supplied to the base of the stove.
- The water at the bottom on heat becomes lighter as the molecules gain more kinetic energy.
- The colder part of the water on top sinks to replace the less dense on below.
- This exchange sets up convection cells in the kettle.
Answer:
Approximately 22.37 days, will it take for the water to be safe to drink.
Explanation:
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
k is rate constant
Given that:- k = 0.27 (day)⁻¹
= 0.63 mg/L
![[A_t]=1.5\times 10^{-3}](https://tex.z-dn.net/?f=%5BA_t%5D%3D1.5%5Ctimes%2010%5E%7B-3%7D)
mg/L
Applying in the above equation as:-
<u>Approximately 22.37 days, will it take for the water to be safe to drink.</u>
The answer is A because I did this before
Buffer solution resist the change in pH upon addition of small amount of strong acid or strong base.
Buffer consists of weak acid as HF / and its conjugate base NaF
When strong acid as HCl is added to buffer, it respond with its conjugate base to convert the strong acid to weak acid like this:
HCl (S.A) + NaF → NaCl + HF (W.A)
moles of HF we already have = M * V(in liters)
= 0.0955 M * 0.033 L = 3.15 x 10⁻³ mole
moles of HCl added = 8.00 x 10⁻⁵ mole
one mole HCl reacts with 1 mole NaF to give 1 mole HF
so the amount added to HF = 8.00 x 10⁻⁵
Total moles of HF present = (3.15 x 10⁻³) + (8.00 x 10⁻⁵) = 3.23 x 10⁻³ mole
