1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonja [21]
3 years ago
15

A 2 microcoulomb charge is placed at a distance of 0.25 m away from a 3.6 microcoulomb charge. Describe the type of electrostati

c force between the charges and calculate the magnitude of the electrostatic force between them.
Physics
2 answers:
EleoNora [17]3 years ago
7 0

Answer: 1.04N

Explanation:

Given

q1 = 2*10^-6C

q2 = 3.6*10^-6C

r = 0.25m

k = 9*10^9

Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."

F =(kq1q2) / r²

F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²

F = 0.0648/0.0625

F = 1.04N

The type of electrostatic force between the charges is the repulsive force

saul85 [17]3 years ago
4 0

Answer:

The force between the charge is a repulsive force

The magnitude of the electrostatic force between them = 1.0368 N

Explanation:

Since both charges are positive charge, and they have the same sign, from the law of electrostatics, The type of force between the charges is Repulsive force.

Using

F = kqq'/r².......................... Equation 1

Where F = Force between the charges, q = first charge, q' = second charge, r = distance between the charges, k = coulombs constant.

Given: q = 2 μC = 2×10⁻⁶ C, q' = 3.6 μC = 3.6×10⁻⁶ C, r = 0.25 m, k = 9×10⁹ Nm²/C²

Substitute into equation 1

F = 9×10⁹(2×10⁻⁶)(3.6×10⁻⁶)/0.25²

F = 64.8×10⁻³/0.0625

F = 1036.8×10⁻³

F = 1.0368 N

Hence the magnitude of the electrostatic force between them = 1.0368 N

You might be interested in
Water is moving at a velocity of 2.00 m/s through a hose with an Internal diameter of 1.60 cm. What is the volume flow rate at t
Leya [2.2K]

Answer:

15 m/s

Explanation:

3 0
2 years ago
using mass and distance, identify and compare the sun's and moon's contribution to the formation of tides on earth
vekshin1

Answer:

Based on its mass, the sun's gravitational attraction to the Earth is more than 177 times greater than that of the moon to the Earth.

7 0
3 years ago
An object is moving east with a constant speed of 30 m/s for 5 seconds. What is the object's acceleration
pentagon [3]

Answer:

<h3>The answer is 6 m/s²</h3>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

where

v is the velocity

t is the time

We have

a =  \frac{30}{5}  \\

We have the final answer as

<h3>6 m/s²</h3>

Hope this helps you

5 0
3 years ago
Ferromagnetic materials-
QveST [7]

Answer:

materials which exhibit a spontaneous net magnetization at the atomic level, even in the absence of an external magnetic field.

Explanation:

When a material is placed within a magnetic field, the magnetic forces of the material's electrons will be affected. This effect is known as Faraday's Law of Magnetic Induction. However, materials can react quite differently to the presence of an external magnetic field. This reaction is dependent on a number of factors, such as the atomic and molecular structure of the material, and the net magnetic field associated with the atoms. The magnetic moments associated with atoms have three origins. These are the electron motion, the change in motion caused by an external magnetic field, and the spin of the electrons.

5 0
3 years ago
A solenoid has a radius Rs = 14.0 cm, length L = 3.50 m, and Ns = 6500 turns. The current in the solenoid decreases at the rate
babymother [125]

Answer:

E = 58.7 V/m

Explanation:

As we know that flux linked with the coil is given as

\phi = NBA

here we have

A = \pi R_s^2

B = \mu_o N i/L

now we have

\phi = N(\mu_o N i/L)(\pi R_s^2)

now the induced EMF is rate of change in magnetic flux

EMF = \frac{d\phi}{dt} = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

now for induced electric field in the coil is linked with the EMF as

\int E. dL = EMF

E(2\pi r_c) = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

E = \frac{\mu_o N^2 R_s^2 \frac{di}{dt}}{2 r_c L}

E = \frac{(4\pi \times 10^{-7})(6500^2)(0.14^2)(79)}{2(0.20)(3.50)}

E = 58.7 V/m

3 0
3 years ago
Other questions:
  • Final velocity for 2.6 seconds
    5·1 answer
  • When does a nebula become a star?
    15·1 answer
  • What is the nature of the distance time graph for motion of an object.
    6·1 answer
  • What is the best description of the chromosomes by the end of metaphase of mitosis?
    10·1 answer
  • explain how an earth wire in an appliance can help to prevent damage or injury to users when a fault occurs in the appliance.
    8·1 answer
  • What causes sedimentary rock to change into metamorphic rock
    7·1 answer
  • 4. Density is a property of all matter.
    7·1 answer
  • When you take your 1900-kg car out for a spin, you go around a corner of radius 55 m with a speed of 15 m/s. The coefficient of
    9·1 answer
  • Does a wheel barrow have mechanical advantage???
    7·1 answer
  • A basketball is tossed upwards with a speed of 5.0 m/s. ​We can ignore air resistance.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!