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Bogdan [553]
3 years ago
6

Identify the name of the compound that goes with this chemical compound

Chemistry
1 answer:
postnew [5]3 years ago
8 0
What is the chemical compound?
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What volume of O2(
irakobra [83]
Answer is: volume of oxygen is 4.63 liters.
Balanced chemical reaction: 2C + O₂ → 2CO.
m(C) = 4.50 g.
n(C) = m(C) ÷ M(C).
n(C) = 4.50 g ÷ 12 g/mol.
n(C) = 0.375 mol.
From chemical reaction: n(C) : n(O₂) = 2 : 1.
n(O₂) = 0.1875 mol.
T = 48°C = 321.15 K.
p = 810 mmHg ÷ 760 mmHg/atm= 1.066 atm.
<span>R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.</span>
V(O₂) = n·R·T / p.<span>
V(O₂) = 0.1875 mol · 0.08206 L·atm/mol·K · 321.15 K / 1.066 atm.</span><span>
V(O₂<span>) = 4.63 L.</span></span>
4 0
3 years ago
Characteristic of meteor​
Sati [7]

Explanation:

Many meteorites have iron or nickel in them, so they are heavier (and denser) than Earth rocks. Some meteorites have pits (regmaglypts) on the outside, which look like deep thumbprints. Meteorites are not bubbly, and do not have holes. Meteorite are usually not round.

8 0
2 years ago
Consider 5.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.50 L and the temperature is increased to 3
pickupchik [31]

First convert celcius to Kelvin.

20 + 273 = 293K

31 + 273 = 304K

Now we can set up an equation based on the information we have.

V1 = 5

P1 = 365

T1 = 293

V2 = 5

P1 = x

T2 = 304

The equation be:  \frac{(5)(365)}{293} = \frac{5x}{304}

Now just solve.

1825/293 = 5x/304

Cross multiply.

554800 = 1465x

Divide both sides by 1465

x = 378.7030717 which can then be rounded to 378.7 mmHg

4 0
2 years ago
The reaction in Fe + O2→Fe2O3 is an example of a(n): A. combination reaction. B. decomposition reaction. C. aqueous reaction. D.
motikmotik
This is a combination reaction because two molecules becomes one

A + B ---> AB
8 0
3 years ago
If temperature is increased , the number of collisions per second
AfilCa [17]

Answer: when the temperature is increased, the number of collisions per second increases.

Explanation:

the rate of collisions and the temperature is directly proportional. If the  energy of the gas particles is boosted by using the temperature, the chances of the particles bumping into each other due to the high energy increases, thus increasing the number of collisions. This also increases the rate of reaction. Thus when temperature is increased the number of collisions also increases.

4 0
3 years ago
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