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attashe74 [19]
2 years ago
6

Helpppp plzzzzz for 20 points

Physics
1 answer:
victus00 [196]2 years ago
7 0

Answer:

only answering without answer bc im annoyed its for 10 points not 20

Explanation:

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A 13.6 kg block is tied at the top of an incline to a tree. If the incline is 35.5 degrees and the coefficient of friction betwe
Gre4nikov [31]

Answer:

Explanation:

ASSUMING that block = sled AND that the rope is parallel to the slope.

The force acting parallel due to the weight is

13.6(9.81)sin35.5 = 77.475 N

The maximum friction force is

(0.45)13.6(9.81)cos35.5 = 48.877 N

If rope tension is T

77.475 - 48.877 < T < 77.475 + 48.877

            28.6 N < T < 126 N

28.6 N will occur if the block is on the verge of sliding downhill

126 N will occur if the block is on the verge of sliding uphill

Could be any value between them.

5 0
3 years ago
An object moving with a constant
jeka57 [31]

Answer:

Acceleration:

{ \tt{a =  \frac{v - u}{t} }} \\ { \tt{a =  \frac{20 - 10}{5} }} \\ { \tt{a = 2 \: m {s}^{ - 2} }}

From third equation:

{ \bf{ {v}^{2}  =  {u}^{2}  + 2as}} \\ { \tt{s =  \frac{ {20}^{2}  -  {10}^{2} }{2 \times 2} }} \\   = { \tt{s = 75 \: m}}

5 0
2 years ago
Read 2 more answers
Please Help Me!
balandron [24]

The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.

<h3>What is image distance?</h3>

This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.

To calculate the image distance, we use the formula below.

Formula:

  • 1/f = 1/u+1/v........... Equation 1

Where:

  • f = Focal length of the mirror
  • v = Image distance
  • u = object distance

From the question,

Given:

  • f = 0.45 m
  • u = 0.25 m

Substitute these values into equation 1 and solve for the image distance

  • 1/0.45 = 1/0.25 + 1/v
  • 2.22 = 4+1/v
  • 1/v = 2.22-4
  • 1/v = -1.78
  • v = 1/(-1.78)
  • v = -0.56 m

Hence, The image distance is -0.56 m.

Learn more about image distance here: brainly.com/question/17273444

5 0
2 years ago
peach pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie pla
zavuch27 [327]

Explanation:

It is given that,

Diameter of the peach pie, d = 9 inches

Radius of the pie, r = 4.5 inches

The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches

Let \theta is the angular distance that the pie plate has moved through.

It is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{183}{4.5}  

\theta=40.66\ radian

Since, 1 radian = 57.29 degrees

\theta=2329.64\ degrees

Since, 1 radian = 0.159155 revolution

\theta=6.47124\ revolution

Hence, this is the required solution.

5 0
3 years ago
Gina made a poster for plastic recycling week and included this information on her poster:
miskamm [114]

Answer:

Gina should put “rubber tires” under “Synthetic.”

Gina should put “starch” under “Natural.”

Explanation: I just did the assignment ;P

4 0
3 years ago
Read 2 more answers
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