3 years ago

Helpppp plzzzzz for 20 points

Physics

1 answer:

victus00 [196]3 years ago

7 0

Answer:

only answering without answer bc im annoyed its for 10 points not 20

Explanation:

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A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?

olga55 [171]

Answer:

17.6 m/s²

Explanation:

Given:

$v_{f}$ = 90 m/s (final velocity)

$v_{i}$ = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

$a_{avg}$ = Δv / Δt

We can find Δv by doing

Δv = $v_{f}$ - $v_{i}$

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

$a_{avg}$ = Δv / Δt

$a_{avg}$ = $\frac{88m/s}{5/s}$

acceleration = 17.6 $m/s^{2}$

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3 years ago

Why is weight considered a force

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As rotational speed increases, thrust____?

never [62]

Increases exponentially is your correct answer

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A construction worker pushes a wheelbarrow with a total mass of 50.0kg. What is the acceleration of the wheelbarrow if the net f

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at what position an object be placed in front of a concave mirror of radius of curvature 40cm so that an erect image of magnific

Thepotemich [5.8K]

C=40cm
f=C/2=40/2=20

$\\ \sf\longmapsto m=\dfrac{f}{f-u}$

$\\ \sf\longmapsto 3=\dfrac{20}{20-u}$

$\\ \sf\longmapsto 3(20-u)=20$

$\\ \sf\longmapsto 60-3u=20$

$\\ \sf\longmapsto 3u=40$

$\\ \sf\longmapsto u=13.3cm$

m=magnification
f is focal length
C is radius of curvature
u is object distance

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3 years ago