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3 years ago

An iron ball is dropped at a height of 10 m from the surface of the moon.

Physics

1 answer:

galben [10]3 years ago

3 0

Answer:

3.51s

Explanation:

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A person is riding on a Ferris wheel of radius R. He starts at the lowest point of the wheel. When the wheel makes one complete

Wittaler [7]

Answering the two questions in reverse order:

-- No. I don't need to know how the speed of the person changed before I can answer the question. I can answer it now.

-- The NET work done by the gravitational force is<em> zero</em>.

-- As the person and his girl-friend go up the first half of the wheel, the motor does positive work and gravity does negative work.

-- After they pass the peak at the top and come down the second half of the wheel, the motor does negative work and gravity does positive work, even though the couple may be interested in other things during that time.

-- The total work done by gravity in one complete revolution is zero.

-- The total work done by the motor in one complete revolution is only what it takes to pay back the energy robbed by friction and air resistance.

4 0

3 years ago

Determine the Reynolds number for a flow of 0.2 m^3/s through a 203 mm inner diameter circular pipe of a fluid with rho=680 kg/m

IrinaK [193]

To find a solution to this problem it is necessary to apply the concepts related to the Reynolds number and its definitions on the type of fluid.

A Reynolds number less than 2000 considers the laminar fluid, while a Reynolds number greater than 4000 is considered a turbulent fluid. (The intermediate between the two values would be a transient fluid)

The mathematical equation that defines the Reynolds number is given by

$Re = \frac{\rho V D}{\mu}$

Where

$\rho =$ Density

V= Velocity

D= Diameter

$\mu =$ Viscosity

Our values are given as

$Q = 0.2m^3/s$

$D = 203*10^{-3}m$

$\rho = 680kg/m^3$

$\mu = 3.1*10^{-4}Ns/m^2$

$\sigma = 0.022N/m$

The velocity can be find through the Discharge equation,

Q = VA

Where

V = Velocity

A = Area

Replacing,

$0.2 = V* (2\pi*(\frac{203*10^{-3}}{2})^2)$

$V = 3.08m/s$

Replacing at the Reynolds equation,

$Re = \frac{\rho VD}{\mu}$

$Re = \frac{680*3.08*203*10^{-3}}{3.1*10^{-4}}$

$Re = 1.37*10^6$

Since Reynolds' number is greater than 4000, then we consider this a turbulent fluid.

3 0

3 years ago

A spring, when compressed 0.20 m from the equilibrium position, stores 24 J. What is the value of the spring constant

Delvig [45]

Given that:

spring compressed ( x) = 0.2 m

Work (W) = 24 J

determine , spring constant (x)=?

We know hat ,

Work (W) = (1/2). k.x²

24 = 1/2 ( k × 0.2²)

48 = k × 0.2²

3 0

3 years ago

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is th

katrin [286]

Complete Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail

Answer:

$F=2*10^{4}N$