The magnitude of force acting on the bumper is 3760 N.
<h3>What is Work energy theorem?</h3>
It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Kinetic energy = 1/2 mv²
Given is a car's bumper designed to withstand 4.32 km/h or 1.2 m/s collision with an immovable object without damage to the body of the car. The bumper cushions the shock by absorbing the force over a distance.
The cushion collapses 0.180 m while bringing 940 kg car to rest from a initial speed of 1.2 m/s
Work done = Force x displacement
As the displacement of the bumper and force acted on it is in same direction, so the work done is
W = Fxcos0° = Fx
The body is coming to rest, so, final velocity is zero. Then, change in kinetic energy will be
ΔK.E = K.Ef - K.Ei
ΔK.E = m/2 (v² - u²)
According to work energy theorem, work done is
W = Fx = m/2 (v² - u²)
Substitute the value and calculate the force,
F = [940 x (0² - 1.2²)] / 2x0.180
F = 3760 N
Thus, the magnitude of force is 3760 N.
Learn more about work energy theorem.
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A transformer is an electrical device that transfers energy between two or more circuits through electromagnetic induction. Transformers are mainly used to increase or decrease voltage in power lines or electric power applications. So your answer would be D. transformer
All of them at the same time if they start off at the same temperature and same volume
Answer:
72.53 mi/hr
Explanation:
From the question given above, the following data were obtained:
Vertical distance i.e Height (h) = 8.26 m
Horizontal distance (s) = 42.1 m
Horizontal velocity (u) =?
Next, we shall determine the time taken for the car to get to the ground.
This can be obtained as follow:
Height (h) = 8.26 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
8.26 = ½ × 9.8 × t²
8.26 = 4.9 × t²
Divide both side by 4.9
t² = 8.26 / 4.9
Take the square root of both side by
t = √(8.26 / 4.9)
t = 1.3 s
Next, we shall determine the horizontal velocity of the car. This can be obtained as follow:
Horizontal distance (s) = 42.1 m
Time (t) = 1.3 s
Horizontal velocity (u) =?
s = ut
42.1 = u × 1.3
Divide both side by 1.3
u = 42.1 / 1.3
u = 32.38 m/s
Finally, we shall convert 32.38 m/s to miles per hour (mi/hr). This can be obtained as follow:
1 m/s = 2.24 mi/hr
Therefore,
32.38 m/s = 32.38 m/s × 2.24 mi/hr / 1 m/s
32.38 m/s = 72.53 mi/hr
Thus, the car was moving at a speed of
72.53 mi/hr.
I believe the answer is option C 1.8 kg•m/s to the east
