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slavikrds [6]
3 years ago
11

Round 15.186 the 1 is underlined.

Mathematics
1 answer:
taurus [48]3 years ago
4 0
15.2 Is the answer...Hope this helps
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Find the rate of change
Zina [86]

“Rate of change” means the same as “slope.”

In algebra, we use the word "slope" to describe how steep a line

is and slope can be found using the ratio rise/run between

any two points that are on that line.

Starting from the point that has the coordinate (-1, -1),

we rise go 1 unit down so our rise is -1 and run 3 units.

So our slope or rise/run is -1/3.

8 0
3 years ago
For brainiest:):):):)::):):):)
scZoUnD [109]

Answer:

The unit rate is accurately \frac{1}{4} (km/minute)

Step-by-step explanation:

(1,1/4) means that the vehicle traveled 1/4 km within 1 minute.

The unit rate for this problem is also known as the speed of the vehicle.

So to find the speed, you need to use distance over time.

---> Unit rate: \frac{1}{4}\\ / 1 = \frac{1}{4} (km/minute)

(2,1/2) means that the vehicle traveled 1/2 km within 2 minutes.

Same process:

---> Unit rate: \frac{1}{2} / 2 =

Because of this, the unit rate is accurately \frac{1}{4} (km/minute)

8 0
2 years ago
Dusty won $125,000 on who wants to be a zillionaire? Game show. He decides to place the money into an account that earns 6.25% i
docker41 [41]

Answer:

kmlk

Step-by-step explanation:

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4 0
3 years ago
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
Rewrite the equation below so that it does not have fractions.
Andru [333]

Answer:

x= - 50/9

Step-by-step explanation:

multipy both equations by 12

9x+60=10

then move the constant to the right hand side and change it's sign

9x= 10 - 60

calculate difference

9x = -50

divide both sides by 9

x= - 50/9

6 0
1 year ago
Read 2 more answers
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