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3 years ago

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Hi can someone pls help it would mean the world to me :)

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kkurt [141]3 years ago

3 0

Answer:

Explanation:

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Calcium has a cubic closest packed structure (fcc) as a solid. Assuming that calcium has an atomic radius of 197 pm, calculate t

Paha777 [63]

Answer:

$1.536 g/cm^3$ is the density of solid calcium.

Explanation:

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density

Z = number of atom in unit cell

M = atomic mass

$(N_{A})$ = Avogadro's number

a = edge length of unit cell

We have:

r = 197 pm = $197\times 10^{-12} m = 197\times 10^{-12}\times 100 cm$

$r=197\times 10^{-10} m$

$a=r\times 2\sqrt{2}$

$a=197\times 10^{-10} m\times 2\sqrt{2}=557.200\times 10^{-10} cm$

M = 40 g/mol

Z = 4

On substituting all the given values , we will get the value of 'a'.

$\rho =\frac{4\times 40 g/mol}{6.022\times 10^{23} mol^{-1}\times (557.200\times 10^{-10} cm)^{3}}$

$\rho =1.536 g/cm^3$

$1.536 g/cm^3$ is the density of solid calcium.

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3 years ago

A weather balloon is inflated to a volume of 2.2 x 10^3 L with 37.4 g of helium. What is the density of helium in grams per lite

Ede4ka [16]

Density = mass/volume
substituting the given values :
We get :
D = 37.4 / 2.2 x 10^3
D = 0.017 grams/liter

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3 years ago

(A) CH3CH2CH2CH3 (B) CH3CH2CH2OH (C) CH3COCH3 (D) CH3COOH (E) CH3CH2CH2NH2 Is the LEAST soluble in

EleoNora [17]

Answer:

either i have no brain or im over thinking it

Explanation:

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3 years ago

A. Monosaccharide with examples

san4es73 [151]

Monosaccharide are
any of the class of sugars (e.g., glucose) that cannot be hydrolyzed to give a simpler sugar.
examples: fructose ,galactose glucose

7 0

3 years ago

Read 2 more answers

Explain how dalton’s atomic theory offered a convincing explanation of the observation that mass is conserved in chemical reacti

podryga [215]

Dalton's atomic theory was based on the law of conservation of mass which states that the matter can neither be created nor be destroyed but it can only transformed into one form or another. In a chemical reaction, total mass of the reactants will be equal to the total mass of the products.

Taking an example,

$methane+oxygen\rightarrow \text{carbon dioxide}+water$

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Mass of $CH_4$ = 16g

Mass of $2O_2$ = $2\times 32g$

Total mass on reactant side = $(16+2\times 32)$

Total mass on reactant side = 80g

Mass of $CO_2$ = 44g

Mass of $2H_2O=2\times 18g$

Total mass on product side = $(44+2\times 18)$

Total mass on product side = 80g

It is seen from the above example that the

total mass on reactant side = total mass on product side.

6 0

3 years ago