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aksik [14]
3 years ago
15

I need help with question B)

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

i cant see the graph, how do you expect us to awser you

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Which equation represents the graph shown?<br> (Picture attached)
Maurinko [17]

Answer:

correct answer is option B

Step-by-step explanation:

as we know equation of line

       y = m x + c....................(1)

where c is the intercept

m is the slope

m = \dfrac{y_2-y_1}{x_2-x_1}

m = \dfrac{35-0}{1-0}

m = 35

putting value of m in equation (1)

we get

y = 35 x + c

from the graph we can clearly see that line is passing through (0,0) hence

0 = 35 (0)x + c

c = 0

hence the equation of line comes out to be

y = 35 x

correct answer is option B

8 0
3 years ago
Help plzz I don't understand this at all.
Zolol [24]
6.4/8 = y/6 = x/7

0.8/1 = 4.8/6 = 5.6/7

6.4/8 = 4.8/6 = 5.6/7

x = 5.6 ; y = 4.8

I think that’s how you do it but not 100% sure
3 0
3 years ago
Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
3 years ago
2. State two (2) values of θ (theta) to the nearest degree for<br> sin θ = − 0. 966
emmasim [6.3K]

Using equivalent angles, the solutions to the equation are given as follows:

\theta = 255^\circ, \theta = 285^\circ

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

In this problem, the equation is:

\sin{\theta} = -0.966

Applying the inverse relation:

\theta = \arcsin{-0.966} = 255^\circ

Which is on the third quadrant. The equivalent angle on the fourth quadrant is given as follows:

270^\circ + (270^\circ - 255^\circ) = 285^\circ

More can be learned about equivalent angles at brainly.com/question/28025397

#SPJ1

5 0
2 years ago
Find the solution of the exponential equation, as in Example 1. (Enter your answers as a comma-separated list.)
yuradex [85]

Answer:

Hello,

Very bad written!!!

Step-by-step explanation:

e^{1-3x}=e^{4x-3}\\\\1-3x=4x-3\\\\7x=4\\\\\boxed{x=\dfrac{4}{7} }\\

8 0
2 years ago
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