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DerKrebs [107]
3 years ago
9

If fog is so bad that I can’t see for short distance what should I do

Engineering
2 answers:
Delvig [45]3 years ago
6 0
It depends what you’re doing...if you’re driving then definitely take things slower and don’t speed. If you’re walking or something then be careful for vehicles and other objects of course.
Annette [7]3 years ago
4 0
Not get in the fog ??
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What is the missing number in the pattern below?<br> 0, 1, 2, 3, 6, 11, 20, _?_, 68
lbvjy [14]

Answer:

0, 1, 2, 3, 6, 11, 20, 37, 68

Explanation:

Each number in the series, starting with 3, is the total of the three numbers before it. The following number is the total of the preceding three numbers, according to the pattern. The pattern's next number is 125.

3 0
3 years ago
Car B is traveling a distance dd ahead of car A. Both cars are traveling at 60 ft/s when the driver of B suddenly applies the br
vagabundo [1.1K]

Answer:

Explanation:

Using the kinematics equation v = v_o + a_ct to determine the velocity of car B.

where;

v_o = initial velocity

a_c = constant deceleration

Assuming the constant deceleration is = -12 ft/s^2

Also, the kinematic equation that relates to the distance with the time is:

S = d + v_ot + \dfrac{1}{2}at^2

Then:

v_B = 60-12t

The distance traveled by car B in the given time (t) is expressed as:

S_B = d + 60 t - \dfrac{1}{2}(12t^2)

For car A, the needed time (t) to come to rest is:

v_A = 60 - 18(t-0.75)

Also, the distance traveled by car A in the given time (t) is expressed as:

S_A = 60  * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2

Relating both velocities:

v_B = v_A

60-12t = 60 - 18(t-0.75)

60-12t =73.5 - 18t

60- 73.5 = - 18t+ 12t

-13.5 =-6t

t = 2.25 s

At t = 2.25s, the required minimum distance can be estimated by equating both distances traveled by both cars

i.e.

S_B = S_A

d + 60 t - \dfrac{1}{2}(12t^2) = 60  * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2

d + 60 (2.25) - \dfrac{1}{2}(12*(2.25)^2) = 60  * 0.75 +60((2.25)-0.75) -\dfrac{1}{2}*18*((2.25)-0.750)^2

d + 104.625 = 114.75

d = 114.75 - 104.625

d = 10.125 ft

3 0
3 years ago
As the amplitude decreases in a wave the energy increasesTrue or false
Montano1993 [528]

Answer:

True

Explanation:

To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

7 0
3 years ago
Do the following addition exercises by translating the numbers into 8-bit 2's complement binary numbers, performing the arithmet
Ganezh [65]

Answer:

I am attaching a file with the solution and explanation as the number character limit is exceeding.

Explanation:

Download docx
8 0
3 years ago
An engine cylinder has a stroke of 320mm and bore 280MM. Calculate the mass of air contained in the cylinder if it is filled wit
belka [17]

Answer:

The mass of the air is 0.0243 kg.

Explanation:

Step1

Given:

Stroke of the cylinder is 320 mm.

Bore of the cylinder is 280 mm.

Pressure of the air is 101.3 kpa.

Temperature of the air is 13°C.

Step2

Calculation:

Stroke volume of the cylinder is calculated as follows:

V=\frac{\pi }{4}d^{2}L

V=\frac{\pi}{4}\times(\frac{280}{1000})^{2}\times(\frac{320}{1000})

V = 0.0197 m³.

Step3

Assume air an ideal gas with gas constant 287 j/kgK. Then apply ideal gas equation for mass of the air as follows:

PV=mRT

m=\frac{PV}{RT}

m=\frac{101.3\times 1000\times 0.0197}{287\times (13+273)}

m= 0.0243 kg.

Thus, the mass of the air is 0.0243 kg.

4 0
3 years ago
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