Answer:
11.92 g ≅ 12.0 g.
Explanation:
- The balanced equation of the reaction is: CO + 2H₂ → CH₃OH.
- The stichiometry shows that 1.0 mole of CO reacts with 2.0 moles of H₂ to produce 1.0 mole of CH₃OH.
- Now, we need to calculate the no. of moles (n) of the reacted CO and H₂ using the relation: <em>n = mass / molar mass.</em>
- No. of moles of CO = mass / molar mass = (14.0 g) / (28.01 g/mol) = 0.4999 mol ≅ 0.5 mol.
- No. of moles of H₂ = mass / molar mass = (1.5 g) / (2.015 g/mol) = 0.7444 mol.
- As showed in the balanced equation: every 1.0 mole of CO needs 2.0 moles of hydrogen to react completely.
- So, for the given data H₂ gas (0.7444 mol) will be the limiting reactant that reacts completely with (0.372 mol) of CO which is in excess (0.5 mol).
- We can get the no. of moles of CH₃OH produced.
<u><em>Using cross multiplication:</em></u>
2 moles of H₂ produce → 1.0 mole of CH₃OH, from the stichiometry.
0.7444 moles of H₂ produce → ??? mole of CH₃OH.
- The no. of moles of CH₃OH produced = (0.7444 moles)(1.0 mole) / (2 moles) = 0.372 mol.
- The amount of CH₃OH produced in grams (mass) = n x molar mass = (0.372 mol) (32.04 g/mol) = 11.92 g ≅ 12.0 g.
I would say that it sounds like you are an alchemist as during the 1500's at least they tried to turn base metals like Pb or lead into Au or gold. While this is not possible, their experiments gave rise to the science and techniques of metallurgy and assaying as confirmed by the great first mine geologist, Georgius Agricola in the 1500's,
3.44x10^2
you move the decimal over to get a single digit number with change. The number of times you move the decimal is the number for the 10 power
Answer:
we need we need to calculate normality of solution to find out gram equivalent of solution