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2 years ago

Criteria and constraints help determine which solutions will be applied when extracting materials from pomace in which way

Chemistry

1 answer:

DedPeter [7]2 years ago

3 0

Answer:

The use of pomace for animal feed might be chosen if minimizing production costs is desired

Explanation:

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A standard lanthanum solution is prepared by dissolving 0.1968 grams of lanthanum oxide (La2O3) in excess nitric acid and diluti

sweet-ann [11.9K]

Answer:

1.208x10⁻³M and 392.5ppm La(NO3)3

Explanation:

The reaction that occurs is:

La2O3 + 6HNO3 → 2La(NO3)3 + 3H2O

Molarity is defined as the moles of solute (In this case, LaO3) per liter of solution. And ppm, are mg of solute per liter of solution.

To solve this question we must find the moles of La(NO3)3 produced and its mass in milligrams to find molarity and ppm:

Moles La2O3 -Molar mass: 325.81g/mol-

0.1968g * (1mol / 325.81g) = 6.04x10⁻⁴ moles La2O3

Moles La(NO3)3:

6.04x10⁻⁴ moles La2O3 * (2mol La(NO3)3 / 1mol La2O3) = 1.208x10⁻³ moles La(NO3)3

Molarity:

1.208x10⁻³ moles La(NO3)3 / 1L =

Mass La(NO3)3 -Molar mass: 324.92g/mol-

1.208x10⁻³ moles La(NO3)3 * (324.92g / mol) = 0.392.5g La(NO3)3

In mg:

392.5mg La(NO3)3 / 1L =

392.5ppm La(NO3)3

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3 years ago

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3 years ago

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Determine the rate law and the value of k for the following reaction using the data provided.CO(g) Cl2(g) → COCl2(g)[CO]i (M)[Cl

marshall27 [118]

Answer: The rate law expression is $\text{Rate}=k[CO]^1[Cl_2]^{\frac{3}{2}}$ and value of 'k' is $11.04M^{-\frac{7}{2}}s^{-1}$

Explanation:

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$CO(g)+Cl_2(g)\rightarrow COCl_2(g)$