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The pressure difference across the sensor housing will be "95 kPa".
According to the question, the values are:
Altitude,
- 9874
Speed,
- 1567 kph
Pressure,
- 122 kPa
The temperature will be:
→
→
→
now,
→
→
hence,
→ The pressure differential will be:
=
=
Thus the above solution is correct.
Learn more about pressure difference here:
Answer:
33.56 ft^3/sec.in
Explanation:
Duration = 6 hours
drainage area = 185 mi^2
constant baseflow = 550 cfs
<u>Derive the unit hydrograph using the inverse procedure </u>
first step : calculate for the volume of direct runoff hydrograph using the details in table 2 attached below
Vdrh = sum of drh * duration
= 29700 * 6 hours ( 216000 secs )
= 641,520,000 ft^3.
next step : Calculate the volume of runoff in equivalent depth
Vdrh / Area = 641,520,000 / 185 mi^2
= 1.49 in
Finally derive the unit hydrograph
Unit of hydrograph = drh / volume of runoff in equivalent depth
= 50 ft^3 / 1.49 in = 33.56 ft^3/sec.in
