A 10MHz clock frequency is applied to a cascaded counter consisting of a modulus-5 counter, a modulus-8 counter and two modulus-

Question

2 years ago

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10 counters. The lowest output frequency available will be:

1 answer:

rewona [7] · Answer 1 · 2023-05-23T06:31:23+03:00

If a clock frequency is applied to a cascaded counter, The lowest output frequency available will be

<h3>Cascade Counter</h3>

For a cascade counter,

Overall frequency = $5*8*10*10$

Overall frequency = $4000$

<h3>Lowest Frequency</h3>

Therefore,

the lowest frequency

$F = \frac{10*10^6}{4*10^3}\\\\F = 2500Hz\\\\F = 2.5kHz$

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