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zubka84 [21]
2 years ago
10

Lisa's Chemistry class was performing an experiment with gas pressures. They filled a container with gas at a pressure of 101,00

0 Pa at room temperature. When they doubled the temperature, the pressure also doubled. What was the new pressure in scientific notation?
Chemistry
1 answer:
Ghella [55]2 years ago
8 0

Answer:

2.02 × 10^5 Pa

Explanation:

According to this question, in an experiment, a container was filled with gas at pressure of 101,000 Pa, at room temperature. When this temperature was doubled, the pressure also increased by two times i.e.

The pressure changed to (101,000 Pa × 2) = 202,000 Pa

This question is asking to represent this in scientific notation. Scientific notation aims at representing a small or too large number in an easy way. It is done by making use of power of ten i.e. a × 10^b

Where; a = decimal number

b = power of ten

In the case of a large number like 202,000, the power of ten is derived by counting the decimal place backwards. If we are to count until we stop in front of the last digit, we will have 5 times.

That is; 2.02000 × 10^5

We can remove every trailing zeros

Hence, the answer is 2.02 × 10^5 Pa.

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Answer:

2 electrons

Explanation:

Oxygen has 6 valence electrons and to be stable it needs 8. That means it needs 2 more electrons to have a full octet.

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When the potential difference across a lamp is 3.3V the current is 0.15 calculate the resistance of the lamp and give the unit
marissa [1.9K]

Answer:

22Ω

Explanation:

Given parameters:

Potential difference  = 3.3V

Current  = 0.15A

Unknown:

Resistance  = ?

Solution:

According to ohm's law, potential difference, current and resistance are related by the expression below;

             V = I R

where V is the voltage

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          R is the resistance

          3.3 = 0.15 x R

             R = \frac{3.3}{0.15}   = 22Ω

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2 years ago
When there is a chemical reaction between hydrochloric acid and potassium hydroxide. Which substances are the reactants? Which s
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Brass is a substitutional alloy consisting of a solution of copper and zinc. A particular sample of red brass consisting of 79.0
Bas_tet [7]

<u>Answer:</u> The molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

<u>Explanation:</u>

Solute is the substance which is present in smaller proportion in a mixture and solvent is the substance which is present in larger proportion in a mixture.

We are given:

(m/m) % of Cu = 79 %

This means that 79 g of copper is present in 100 grams of alloy.

(m/m) % of Zn = 21 %

This means that 21 g of zinc is present in 100 grams of alloy.

As, zinc is present in smaller proportion. So, it is solute and copper is the solvent.

  • <u>Calculating molality of zinc:</u>

To calculate molality of the zinc, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

m_{solute} = Given mass of solute (Zinc ) = 21 g

M_{solute} = Molar mass of solute (Zinc) = 65.3 g/mol

W_{solvent} = Mass of solvent (copper) = 79 g

Putting values in above equation, we get:

\text{Molality of Zinc}=\frac{21\times 1000}{65.3\times 79}\\\\\text{Molality of zinc}=4.07m

  • <u>Calculating molarity of zinc:</u>

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 8740kg/m^3=\frac{8740kg\frac{1000g}{1kg}}{1m^3\times \frac{10^6cm^3}{1m^3}}=\frac{8740g}{1000cm^3}=8.740g/cm^3

(Conversion factors used are:  1 kg = 1000 g &  1m^3=10^6cm^3  )

Mass of solution = 100 g

Putting values in above equation, we get:

8.740g/cm^3=\frac{100.0g}{\text{Volume of zinc}}\\\\\text{Volume of zinc}=11.44cm^3

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molar mass of zinc = 65.3 g/mol

Volume of solution = 11.44cm^3=11.44mL     (Conversion factor:  1cm^3=1mL  )

Mass of zinc = 21.0 g

Putting values in above equation, we get:

\text{Molarity of zinc}=\frac{21\times 1000}{65.3\times 11.44}=28.11M

Hence, the molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

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What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?
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Answer:

Explanation:

Na + Cl2 —> NaCl

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