<u>Answer:</u>
<u>For a:</u> The volume of HCl needed is 4.52 mL
<u>For b:</u> The volume of HCl needed is 25.63 mL
<u>For c:</u> The volume of HCl needed is 43.33 mL
<u>Explanation:</u>
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid
are the n-factor, molarity and volume of base
We are given:
Putting values in above equation, we get:
Hence, the volume of HCl needed is 4.52 mL
We are given:
Putting values in above equation, we get:
Hence, the volume of HCl needed is 25.63 mL
To calculate the molarity of solution, we use the equation:
Given mass of NaOH = 1.40 g
Molar mass of NaOH = 40 g/mol
Volume of solution = 1 L
Putting values in above equation, we get:
We are given:
Putting values in above equation, we get:
Hence, the volume of HCl needed is 43.33 mL