Calcium carbonate has the formula: CaCO3
From the periodic table:
mass of calcium = 40 grams
mass of carbon = 12 grams
mass of oxygen = 16 grams
Therefore,
molar mass of CaCO3 = 40 + 12 + 3(16) = 100 grams
molar mass of carbonate = 12 + 3(16) = 60 grams
One mole of calcium carbonate contains one mole of carbonate. Therefore, 100 grams of CaCO3 contains 60 grams of CO3.
If the 0.5376 grams of the unknown substance is CaCO3, then the amount of carbonate will be:
amount of carbonate = (0.5376*60) / 100 = 0.32256 grams
Based on the above calculations, the sample is not CaCO3
Answer:
Explanation:
Hello,
In this case, for the given information, we can compute the rate of disappearance of NO₂ by using the following rate relationship:
Whereas it is multiplied by the the inverse of the stoichiometric coefficient of NO₂ in the reaction that is 2. Moreover, the subscript <em>f</em> is referred to the final condition and the subscript <em>0</em> to the initial condition, thus, we obtain:
Clearly, it turns out negative since the concentration is diminishing due to its consumption.
Regards.
Answer: Option (4) is the correct answer.
Explanation:
It is known that density is mass divided by volume.
Mathematically, Density = 
Since, density is directly proportional to mass. So, more is the mass of an element more will be its density.
Mass of magnesium is 24.305 g/mol.
Mass of barium is 137.327 g/mol.
Mass of beryllium is 9.012 g/mol
Mass of radium is 226 g/mol.
Hence, radium has more mass therefore it will have the greatest density at STP.
2n+a is the simplified expression
Answer:
D. Z, X, Y
Explanation:
Step 1: Z
Within the Sun two protons fuse together and when this proton-proton pair breaks apart one proton transform into neutron due to weak nuclear force. Along with transformation of neutron, a positron also formed and proton-neutron pair sometimes form deuterium.
Step 2: X
Collision of third proton takes place with deuterium and this collision results in formation of Helium-3 along with gamma rays. These gamma rays are also released as sunlight.
Step 3: Y
Collision of two Helium-3 nuclei takes place which results in creation of Helium-4.
