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vichka [17]
3 years ago
11

D Which compound is insoluble in water?

Chemistry
1 answer:
densk [106]3 years ago
3 0

Answer:

Examples of substances insoluble in water: oil, acetone, ether

Explanation:

Such examples of substances are non-polar and do not dissolve in water (polar compound). The classic example is oil floating in water (this happens because oil has a lower density than water).

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Can I use the sap of jackfruit to be used into a glue?
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Yes as there is advertisements for this as a alternative to glue.<span />
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When HClO2 is dissolved in water, it partially dissociates according to the equation
Natasha_Volkova [10]

Answer:

x = 100 * 1.1897 = 118.97 %, which is > 100 meaning that all of the HClO2 dissociates

Explanation:

Recall that , depression present in freezing point is calculated with the formulae = solute particles Molarity x KF

0.3473 = m * 1.86

Solving, m = 0.187 m

Moles of HClO2 = mass / molar mass = 5.85 / 68.5 = 0.0854 mol

Molality = moles / mass of water in kg = 0.0854 / 1 = 0.0854 m

Initial molality

Assuming that a % x of the solute dissociates, we have the ICE table:

                 HClO2         H+    +   ClO2-

initial concentration:       0.0854                    0             0

final concentration:      0.0854(1-x/100)   0.0854x/100   0.0854x / 100

We see that sum of molality of equilibrium mixture = freezing point molality

0.0854( 1 - x/100 + x/100 + x/100) = 0.187

2.1897 = 1 + x / 100

x = 100 * 1.1897 = 118.97 %, which is > 100 meaning that all of the HClO2 dissociates

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3 years ago
Iodine-131 is used to
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_NaHCO(s) --&gt; _CO2+_NaCO(s)+_H2O<br><br>balance the equation​
elena55 [62]

The balanced equation :

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

<h3>Further explanation</h3>

Given

Reaction

NaHCO(s) --> _CO2+_NaCO(s)+_H2O

Required

The balanced equation

Solution

Maybe the equation should be like this :

NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

Give a coefficient

NaHCO₃⇒aCO₂ + bNa₂CO₃+cH₂O

Make an equation

Na, left=1, right=2b⇒2b=1⇒b=1/2

H, left=1, right=2c⇒2c=1⇒c=1/2

C, left=1, right=a+b⇒a+b=1⇒a+1/2=1⇒a=1/2

The equation becomes :

NaHCO₃⇒1/2CO₂ +1/2Na₂CO₃+1/2H₂O x2

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

5 0
2 years ago
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