Answer:
Wendy is filling in party goodie bags with toy cars and helicopters. There are 56 toy cars and 77 helicopters. Each bag must only have either toy car or helicopter - there is no mixing of toys.
Each bag must have the same number of toy cars in it.
Each bag must have the same number of toy helicopter in it.
All bags must have the same number of toys in it.
a) How many bags will contain toy cars?
b) How many bags will contain toy helicopters?
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Answer:
Think of highest common factor of 56 and 77
Both numbers are divisible by 1, 2, and 7 and the highest common factor is 7
56 ÷ 7 = 8
77 ÷ 7 = 11
There are 8 bags that contain equal numbers of toy cars and 11 bags that contain equal number of helicopter toy
I give all credit to merlynthewhizz who created this answer on BRAINLY.com
