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4 years ago

Give two examples of common force fields and name the sources of these fields.

Physics

1 answer:

algol134 years ago

4 0

Electric force from electomagnetic force and force of gravity from gravitational force

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Which is a device made from a coil of wire that carries a current and produces a magnetic field?

slega [8]

A device made from a coil of wire that carries a current and produces a magnetic field is called a solenoid. ✅

Answer: Letter B

Hope that helps. -UF aka Nadia

8 0

3 years ago

Read 2 more answers

How do I find the speed of sound when given Frequency and displacement?

IceJOKER [234]

Answer: Taking into account sound is a wave, we can use the information of the displacement (generally given as a graph) to find the wavelength and frequency, then we can calculate the speed with the formula of the speed of a wave.

Explanation:

If we have the displacement graph of the sound wave, we can find its amplitude, its wavelength and period (which is the inverse of frequency).

Now, if we additionally have the frequency as data, we can use the equation of the speed of a wave:

$s=\lambda f$

Where:

$s$ is the speed of the sound wave

$\lambda$ is the wavelength

$f$ is the frequency

3 0

3 years ago

a rectangular block weighs 240N. The area of the block in contact with the floor is 20cm2 calculate the pressure on the floor

Romashka [77]

Answer:

The pressure on the floor is 12 Pascal(Pa).

Explanation:

Given,

Force (F) = 240N

Area (A) = 20 cm^2

Pressure (P) = ?

we know that,

P = F/A

= 240/ 20

= 12 Pa

8 0

3 years ago

A very small object with mass 8.30×10-9 kg and positive charge 6.90×10-9 C is projected directly toward a very large insulating

Rainbow [258]

Answer:

$41.4496148484\ m/s$

Explanation:

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

$\sigma$ = Surface charge density = $5.9\times 10^{-8}\ C/m^2$

$\Delta x$ = 0.57-0.26

q = Charge = $6.9\times 10^{-9}\ C$

m = Mass of object = $8.3\times 10^{-9}\ kg$

Electric field due to a sheet is given by

$E=\dfrac{\sigma}{2\epsilon_0}\\\Rightarrow E=\dfrac{5.9\times 10^{-8}}{2\times 8.85\times 10^{-12}}\\\Rightarrow E=3333.33\ V/m$

Electric field is given by

$E=\dfrac{V}{d}$

Voltage is given by

$V=E\Delta x$

Kinetic energy is given by

$K=qV$

$\dfrac{1}{2}mv^2=qE\Delta x\\\Rightarrow v=\sqrt{\dfrac{2qE\Delta x}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 6.9\times 10^{-9}\times 3333.33\times (0.57-0.26)}{8.3\times 10^{-9}}}\\\Rightarrow v=41.4496148484\ m/s$

The initial speed of the object is $41.4496148484\ m/s$

7 0

3 years ago

A force of 120 N is applied to an object whose mass is 30 kg. The object's acceleration is:

Airida [17]

Answer:

C) 4.0 m/s²

Explanation:

Given data

Applied force (F): 120 Newton

Mass of the object (m): 30 kilograms

Acceleration of the object (a): to be determined

We can find the acceleration of the object using Newton's second law of motion.

F = m . a

a = F / m = 120 N / 30 kg = 4.0 m/s²

The acceleration of the object is 4.0 m/s².

8 0

3 years ago