Use the formula B(at the center)= (4 pi * 10^(-7) ) * I (current) / ( 2 radius)
and you will get the answer that will be 6.
Answer:
To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.
Answer:
The oscillation frequency of the spring is 1.66 Hz.
Explanation:
Let m is the mass of the object that is suspended vertically from a support. The potential energy stored in the spring is given by :

k is the spring constant
x is the distance to the lowest point form the initial position.
When the object reaches the highest point, the stored potential energy stored in the spring gets converted to the potential energy.

Equating these two energies,

.............(1)
The expression for the oscillation frequency is given by :

(from equation (1))

f = 1.66 Hz
So, the oscillation frequency of the spring is 1.66 Hz. Hence, this is the required solution.
We have:
s=3,7km (3700m)
u=0
v=26m/s
a=
t=
We look up for a formula to solve for a:
v²=u²+2as u²=0 so
v²=2as
(26m/s)²=2a3700m
676/7400=a
a=0,09m/s²
Answer:
Projectile motion is the motion of an object thrown (projected) into the air. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.
Explanation: