Q = mc[change in]T
Q = 0.23 * 4200 * 15
Q = 14490J
Across
1: Period
5: Proton
Down
2: Electron
3: Neutron
More later, I've gotta do homework now :)
Answer:
protons+neutrons = atomic mass
11+12 = 23
so the element which has an atomic mass of 23 is
<h2>Sodium (Na)</h2>
For the equilibrium that exists in an aqueous solution<span> of nitrous acid (</span>HNO2, a weak acid) ... [H+][NO2. –]. [HNO2<span>]. PAGE: 14.1. 2. Which of the following is a conjugate ... Using the following Ka values, indicate the correct </span>order<span> of base strength. </span>HNO2<span>. Ka = </span>4.0<span> × 10–4 .... Calculate the [H+] in a </span>solution<span>that has a </span>pH<span> of 11.70.
i hope thid works
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