What does an aluminum atom become when it loses its three valence electrons? a?
1 answer:
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Answer: It will take 29 years for a 10.0-gram sample of strontium-90 to decay to 5.00 grams
Explanation:
Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
Half life is represented by
= rate constant
Given : Strontium-90 decreases in mass by one-half every 29 years , that is half life of Strontium-90 is 29 years.
As half life is independent of initial concentration, it will take 29 years for a 10.0-gram sample of strontium-90 to decay to 5.00 grams as the amount gets half.
Answer:
a) HCl is the limiting reagent.
b) Mass of NH₄Cl formed = 6.68 g
c) Pressure of the gas remaining in the flask = 1.742 atm
Explanation:
The complete Question is presented in the attached image to this solution.
To solve this question, we first need to obtain the limiting regaent for this reaction.
The limiting reagent is the reagent that is in short supply in the reaction and is used up in the reaction. It determines the amount of products that will be formed and the amount of other reactants that will be required for the reaction.
NH₃ (g) + HCl (g) ⟶ NH₄Cl (s)
1 mole of NH₃ reacts with 1 mole of HCl
we first convert the masses of the gases available to number of moles.
Number of moles = (Mass/Molar Mass)
Molar mass of NH₃ = 17.031 g/mol, Molar mass of HCl = 36.46 g/mol
Number of moles of NH₃ = (4.55/17.031) = 0.2672 mole
Number of moles of HCl = (4.55/36.46) = 0.1248 mole
Since 1 mole of NH₃ reacts with 1 mole of HCl
It is evident that HCl is in short supply and is the limiting reagent.
NH₃ is in excess.
So, to calculate the amount of NH₄Cl formed,
1 mole of HCl gives 1 mole of NH₄Cl
0.1248 mole of HCl will also gove 0.1248 mole of NH₄Cl
Mass (Number of moles) × (Molar Mass)
Molar mass of NH₄Cl = 53.491 g/mol
Mass of NH₄Cl formed = 0.1248 × 53.491 = 6.68 g
c) The gas remaining in the flask is NH₃
0.1248 mole of NH₃ is used up for the reaction, but 0.2672 mole was initially available for reaction,
The amount of NH₃ left in the reacting flask is then
0.2672 - 0.1248 = 0.1424 mole.
Using the ideal gas Equation, PV = nRT
We can obtain the rrequired pressure of the remaining gas in the flask
P = Pressure = ?
V = Volume = 2.00 L
n = number of moles = 0.1424 mole
R = molar gas constant = 0.08205 L.atm/mol.K
T = absolute temperature in Kelvin = 25 + 273.15 = 298.15 K
P = (nRT/V)
P = (0.1424×0.08205×298.15/2) = 1.742 atm
Hope this Helps!!!
