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WINSTONCH [101]
3 years ago
12

Pls help I’ll mark brainliest

Chemistry
1 answer:
Fudgin [204]3 years ago
6 0

Answer: I will answer if u Mark me

Explanation:

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Pls help! Will mark brainliest! 55 Points!​
GenaCL600 [577]

Answer:

7cm square is the answer

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3 years ago
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Omg imgonnafailnfiedkla
Flura [38]

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Glucose and oxygen are required for cellular respiration. As the law of conversation states, in a biochemical reaction, mass is conserved. The mass of hydrogen in the glucose is therefore conserved in the water molecules products.

4 0
3 years ago
WHAT IS THE MOLAR MASS FOR AMMONIUM SULFIDE?<br> A. 59.1g/mol<br> B.82.2g/mol<br> C.50.1g/mol
Jobisdone [24]

Answer:

68g/mol

Explanation:

The formula of ammonium sulfide is:

 Ammonium sulfide  = (NH₄)₂S

 The molar mass of a compound is the mass in gram of one mole of the substance. In a compound, it is expressed gram formula mass or gram-molecular weight.

 It is determined by the addition of the component atomic masses and then expressed in grams;

     Atomic mass of N = 14, H  = 1 and S = 32

 (NH₄)₂S  = 2[14 + 4(1)] + 32  = 36 + 32  = 68g/mol

3 0
2 years ago
You have used 2.6×102 L of distilled water for a dialysis patient. How many gallons of water is that?
Vitek1552 [10]

Answer:

63 gallons of distilled water

4 0
3 years ago
Consider the following chemical reaction: CO (g) + 2H2(g) ↔ CH3OH(g) At equilibrium in a particular experiment, the concentratio
boyakko [2]

Answer:

The concentration of CH₃OH in equilibrium is [CH₃OH] = <em>2,8x10⁻¹ M</em>

Explanation:

For the equilibrium:

CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5

Thus:

14,5 = \frac{[CH_{3}OH]}{[CO][H_{2}]^2}

In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:

14,5 = \frac{[CH_{3}OH]}{[0,15][0,36]^2}

Solving, the concentration of CH₃OH in equilibrium is:

<em>[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M</em>

I hope it helps!

8 0
3 years ago
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