Answer:
x = -8 and x = 4
Step-by-step explanation:
given
f(x) = (x+8) (x - 4)
recall that at any point on the x-axis, y = 0 [i.e f(x) = 0]
hence to find where the graph crosses the x-axis, we simply substitue f(x) = 0 into the equation and solve for x
f(x) = (x+8) (x - 4)
0 = (x+8) (x - 4)
Hence
either,
(x+8) = 0 ----> x = -8 (first crossing point)
or
(x-4) = 0 ------> x = 4 (second crossing point)
Hence the graph crosses the x-axis at x = -8 and x = 4
Answer:
Option (c) "
"
Step-by-step explanation:
The given equation is :
q = c4(h + r)
We need to solve it for r.
Dividing both sides of the given equation by 4c.
Now, subtract h both sides of the equation.
Hence, this is the required solution.
Y= 3x - 10
<span>3x + 2y = 16
3x+2(3x-10)=16
3x+6x-20=16
9x-20=16
9x=36
x=4
y=3x-10
y=3(4)-10
y=12-10
y=2</span>
Answer: p= -3/13
Step-by-step explanation:
-10+26p=-16
+10 +10
26p =-6
26 26
p= -3/13
Answer:
64a³c²⁷
Step-by-step explanation:
The expression inside parentheses can be simplified by noting that b^0 = 1. Then you have ...
(4ac^9)^3
The rules of exponents say the exponent outside applies to each of the inside factors. For c^9, the exponents multiply.
Here are the applicable rules:
(ab)^c = (a^c)(b^c)
(a^b)^c = a^(b·c)
__
(4ac^9)^3 = 4^3·a^3·c^(9·3) = 64a^3c^27
