Answer:
The voltage amplitude of the source is 212.25 V
Explanation:
Given;
frequency of the circuit, F = 50-Hz
resistance across the circuit, R = 50-ohm
capacitance, C = 60 microfarad
inductance, L = 0.50-H
rms current in the circuit, = 1.3 A
where;
is peak current
Also, the voltage amplitude of the source is given as;
where;
Z is impedance calculated as;
is inductive reactance, calculated as;
is capacitive reactance, calculated as;
Finally, the voltage amplitude of the source:
Therefore, the voltage amplitude of the source is 212.25 V