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Paha777 [63]
3 years ago
12

25 points!!! PLEASE HELP ASAP please answer both of these with work shown!!

Chemistry
2 answers:
Contact [7]3 years ago
4 0

Answer:

1) Pressure = 16.9 atm

2) The volume needed is 11.5 L

Explanation:

What pressure is exerted by 0.450 mol of a gas at 25°C if the gas is in a 0.650-L container?

p*V = n*R*T

⇒with p = the pressure = TO BE DETERMINED

⇒with V = the volume of the container = 0.650 L

⇒with n =the number of moles of gas = 0.450 moles

⇒ with R = the gas constant = 0.08206 L*atm /mol*K

⇒ with T = the temperature = 25 °C = 298 K

p = (n*R*T)/V

p = (0.450 * 0.08206 * 298) / 0.650

p = 16.9 atm

The recommended air pressure of a car tire is 32.0 psi (221 kPa). An average tire holds

around 1 mole of gas. What is the volume of the tire at 32°C?

p*V = n*R*T

⇒with p = the pressure = 32.0 psi = 221 kPa = 2.18 atm

⇒with V = the volume of the tire = TO BE DETERMINED

⇒with n =the number of moles of gas = 1.0 mol

⇒ with R = the gas constant = 0.08206 L*atm /mol*K

⇒ with T = the temperature = 32 °C = 305 K

V = (n*R*T) / p

V = 1.0 * 0.08206 * 305) / 2.18

V = 11.5 L

liq [111]3 years ago
3 0

Answer:

The answer to your question is below

Explanation:

1.-

Data

Pressure = ?

moles = 0.450

temperature = 25°C

Volume = 0.650 L

R = 0.082 atm L / mol °K

1) Convert temperature to °K

°K = 25 + 273

    = 298°K

2) Use the Ideal gas law to solve this problem

     PV = nRT

- Solve for P

     P = nRT / V

- Substitution

      P = (0.45)(0.082)(298) / 0.65

- Result

      P = 16.91 atm

2.-

Pressure = 221 kPa

moles = 1

Volume = ?

Temperature = 32°C

R = 0.082 atm L /mol°K

Process

1) Convert pressure to atm

Pressure = 221 kPa = 221000 Pa

                   1 atm ----------------- 101325 Pa

                    x      ------------------ 221000 Pa

                    x = (221000 x 1)/101325

                    x = 2.18 atm

2.- Convert temperature to °K

°K = 273 + 32 = 305°

3.- Substitution

     PV = nRT

- Solve for V

     V = nRT / P

- Substitution

     V = (1)(0.082)(305) / 2.18

- Result

      V = 11.47 L      

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ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0
3 years ago
What two things do all matter have in common?
ELEN [110]

Answer:

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Explanation:

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What best describes the conditions to becoming a fossil
Ede4ka [16]
Hello

I don't quite understand the question your asking and if there is any answers provided but I will still give you mine.


Fossils are formed in a number of different ways, but most are formed when a plant or animal dies in a watery environment and is buried in mud and silt. Soft tissues quickly decompose leaving the hard bones or shells behind. Over time sediment builds over the top and hardens into rock.


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Have a nice day!!
3 0
3 years ago
Which are the hybrid orbitals of the carbon atoms in the following molecules? (a) H3C―CH3 sp sp2 sp3 (b) H3C―CH═CH2 sp sp2 sp3 (
kherson [118]

Answer:

(a)  sp³    sp³

   H₃<u>C</u> - <u>C</u>H₃

(b)     sp³           sp²

     H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

                sp²

(c)     sp³        sp    

    H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

              sp         sp³

(d)     sp³    sp²    

       H₃<u>C</u> - <u>C</u>H=O

Explanation:

Alkanes or the carbons with all the single bonds are sp³ hybridized.

Alkenes or the carbons with double bond(s) are sp² hybridized.

Alkynes or the carbons with triple bond are sp hybridized.

Considering:

(a) H₃C-CH₃ , Both the carbons are bonded by single bond so both the carbons are sp³ hybridized.

Hence,

 sp³    sp³

H₃<u>C</u> - <u>C</u>H₃

(b) H₃C-CH=CH₂ , The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp² hybridized because they are bonded by double bond.

Hence,

   sp³           sp²

H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

         sp²

(c) H₃C-C≡C-CH₂OH , The carbons of the methyl group and alcoholic group are sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp hybridized because they are bonded by triple bond.

Hence,

   sp³        sp    

H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

         sp         sp³

(d)CH₃CH=O, The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The other carbon is sp² hybridized because it is  bonded by double bond to oxygen.

Hence,

   sp³    sp²    

 H₃<u>C</u> - <u>C</u>H=O

     

8 0
3 years ago
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