Answer : The percentage reduction in intensity is 79.80 %
Explanation :
Using Beer-Lambert's law :
![A=\epsilon \times C\times l](https://tex.z-dn.net/?f=A%3D%5Cepsilon%20%5Ctimes%20C%5Ctimes%20l)
![A=\log \frac{I_o}{I}](https://tex.z-dn.net/?f=A%3D%5Clog%20%5Cfrac%7BI_o%7D%7BI%7D)
![\log \frac{I_o}{I}=\epsilon \times C\times l](https://tex.z-dn.net/?f=%5Clog%20%5Cfrac%7BI_o%7D%7BI%7D%3D%5Cepsilon%20%5Ctimes%20C%5Ctimes%20l)
where,
A = absorbance of solution
C = concentration of solution = ![3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}](https://tex.z-dn.net/?f=3.25mmol.dm%5E%7B3-%7D%3D3.25%5Ctimes%2010%5E%7B-3%7Dmol.dm%5E%7B-3%7D)
l = path length = 2.5 mm = 0.25 cm
= incident light
= transmitted light
= molar absorptivity coefficient = ![855dm^3mol^{-1}cm^{-1}](https://tex.z-dn.net/?f=855dm%5E3mol%5E%7B-1%7Dcm%5E%7B-1%7D)
Now put all the given values in the above formula, we get:
![\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)](https://tex.z-dn.net/?f=%5Clog%20%5Cfrac%7BI_o%7D%7BI%7D%3D%28855dm%5E3mol%5E%7B-1%7Dcm%5E%7B-1%7D%29%5Ctimes%20%283.25%5Ctimes%2010%5E%7B-3%7Dmol.dm%5E%7B-3%7D%29%5Ctimes%20%280.25cm%29)
![\log \frac{I_o}{I}=0.6947](https://tex.z-dn.net/?f=%5Clog%20%5Cfrac%7BI_o%7D%7BI%7D%3D0.6947)
![\frac{I_o}{I}=10^{0.6947}=4.951](https://tex.z-dn.net/?f=%5Cfrac%7BI_o%7D%7BI%7D%3D10%5E%7B0.6947%7D%3D4.951)
If we consider
= 100
then, ![I=\frac{100}{4.951}=20.198](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B100%7D%7B4.951%7D%3D20.198)
Here 'I' intensity of transmitted light = 20.198
Thus, the intensity of absorbed light
= 100 - 20.198 = 79.80
Now we have to calculate the percentage reduction in intensity.
![\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7Breduction%20in%20intensity%7D%3D%5Cfrac%7BI_A%7D%7BI_o%7D%5Ctimes%20100)
![\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7Breduction%20in%20intensity%7D%3D%5Cfrac%7B79.80%7D%7B100%7D%5Ctimes%20100%3D79.80%5C%25)
Therefore, the percentage reduction in intensity is 79.80 %
Answer:
C. The more niches in an ecosystem, the greater the biodiversity.
Explanation:
Answer:
Do you need the definition or the equation to find it?
Explanation:
Equation:
Mass=volume x density
Answer:
- <u>Tellurium (Te) and iodine (I) are two elements </u><em><u>next to each other that have decreasing atomic masses.</u></em>
Explanation:
The <em>atomic mass</em> of tellurium (Te) is 127.60 g/mol and the atomic mass of iodine (I) is 126.904 g/mol; so, in spite of iodine being to the right of tellurium in the periodic table (because the atomic number of iodine is bigger than the atomic number of tellurium), the atomic mass of iodine is less than the atomic mass of tellurium.
The elements are arranged in increasing order of atomic number in the periodic table.
The atomic number is equal to the number of protons and the mass number is the sum of the protons and neutrons.
The mass number, except for the mass defect, represents the atomic mass of a particular isotope. But the atomic mass of an element is the weighted average of the atomic masses of the different natural isotopes of the element.
Normally, as the atomic number increases, you find that the atomic mass increases, so most of the elements in the periodic table, which as said are arranged in icreasing atomic number order, match with increasing atomic masses. But the relative isotope abundaces of the elements can change that.
It is the case that the most common isotopes of tellurium have atomic masses 128 amu and 130 amu, whilst most common isotopes of iodine have an atomic mass 127 amu. As result, tellurium has an average atomic mass of 127.60 g/mol whilst iodine has an average atomic mass of 126.904 g/mol.
Answer:
True
Explanation:
Sometimes you will need to convert from grams to moles, or moles to grams