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rusak2 [61]
3 years ago
5

(11%) Problem 5: A uniform stationary ladder of length L = 2.7 m and mass M = 11 kg leans against a smooth vertical wall, while

its bottom legs rest on a rough horizontal floor. The coefficient of static friction between floor and ladder is μ = 0.45. The ladder makes an angle θ = 51° with respect to the floor. A painter of mass 8M stands on the ladder a distance d from its base. show answer No Attempt 33% Part (a) Find the magnitude of the normal force N, in newtons, exerted by the floor on the ladder.
Physics
1 answer:
jeka943 years ago
7 0

Answer:

970.2 N

Explanation:

We are given that

Length of ladder=2.7 m

Mass,M=11 kg

Coefficient of friction=\mu=0.45

\theta=51^{\circ}

Mass of painter=8M

Distance from base=d

We have to find the magnitude of the normal force exerted by the floor on the ladder.

Normal force exerted by floor on the ladder=mg+8mg=9mg

Where g=9.8m/s^2

Normal force exerted by floor on the ladder=9\times 11\times 9.8=970.2N

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