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luda_lava [24]
2 years ago
7

Phyllis is calculating the path of a space probe that will travel to Pluto. On the way to Pluto, the probe will pass Mars, Satur

n, Jupiter, and Neptune.
Which of those planets exerts the greatest gravitational force?
Mars
Saturn
Jupiter
Neptune
Physics
2 answers:
docker41 [41]2 years ago
5 0

Answer:

jupiter

Explanation:

biggest planet strongest gravitational force

inysia [295]2 years ago
4 0

Answer:

Jupiter

Explanation:

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Third model shows how a comet's tail changes during its orbit...

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2 years ago
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Water flows straight down from an open faucet. The cross-sectional area of the faucet is 2.4 × 10-4m2 and the speed of the water
Ksenya-84 [330]

To solve this problem it is necessary to apply the continuity equations in the fluid and the kinematic equation for the description of the displacement, velocity and acceleration.

By definition the movement of the Fluid under the terms of Speed, acceleration and displacement is,

v_2^2 = v_1^2 + 2gh

Where,

V_i = Velocity in each state

g= Gravity

h = Height

Our values are given as,

A_1 = 2.4*10^{-4} m^2

v_1 = 0.8 m/s

h = 0.11m

Replacing at the kinetic equation to find V_2 we have,

v_2 = \sqrt{v_1^2 + 2gh}

v_2 = \sqrt{(0.8 m/s)^2 + 2(9.80 m/s2)(0.11 m)}

v_2= 1.67 m/s

Applying the concepts of continuity,

A_1v_1 = A_2v_2

We need to find A_2 then,

A_2= \frac{A_1v_1 }{v_2}

So the cross sectional area of the water stream at a point 0.11 m below the faucet is

A_2= \frac{A_1v_1 }{v_2}

A_2= \frac{(2.4*10^{-4})(0.8)}{(1.67)}

A_2= 1.14*10^{-4} m2

Therefore the cross-sectional area of the water stream at a point 0.11 m below the faucet is 1.14*10^{-4} m2

8 0
3 years ago
All of these are types of electromagnetic waves except for:
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3 0
2 years ago
How long would it take for Sofia to walk 300 meters if she is walking at a velocity of 2.5 m/s?
Vaselesa [24]

Answer:

Time=120seconds

Explanation:

S=300m

V=2.5m/s

t=?

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7 0
3 years ago
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A 45 kg bear slides, from rest, 11 m down a lodgepole pine tree, moving with a speed of 5.8 m/s just before hitting the ground.
Viefleur [7K]

Answer:

Explanation:

a )

change  in the gravitational potential energy of the bear-Earth system during the slide  = mgh

= 45 x 9.8 x 11

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b )

kinetic energy of bear just before hitting the ground

= 1/2 m v²

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c ) If  the average frictional force that acts on the sliding bear be F

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4851 J -  F x 11 =  756.9 J

F x 11 = 4851 J -   756.9 J

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F = 4094.1 / 11

= 372.2 N  

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3 years ago
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