The assumption is Originally at 20°C
Now
We need ∆T
- Q=mc∆T
- 1=1(0.108)∆T
- 0.108∆T=1
- ∆T=1/0.108=9.26°C
Now
- ∆T=T_f-20
- 9.26=T_f-20
- T_f=29.26°C
Option A
Answer:
Time required is 1.33 seconds
Explanation:
For first order reaction, the rate law expression is:
![kt = ln \frac{[A_{0}]}{[A_{t}]}](https://tex.z-dn.net/?f=kt%20%3D%20ln%20%5Cfrac%7B%5BA_%7B0%7D%5D%7D%7B%5BA_%7Bt%7D%5D%7D)
Where
A0 = initial concentration = 0.830 M
At = concentration after time t = 0.260 M
t = time in seconds = ?
k = rate constant = 0.870 s⁻¹
time = ](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7Bk%7D%5D%28ln%5B%5Cfrac%7B0.830%7D%7B0.260%7D%5D%29)
time = 
Answer:
in 5 day in total are 7200 mins
Each oxygen will have the oxidation number (2-), and we know the total charge is 1-. We have four oxygen atoms per molecule, so we can set up the equation:
(charge on Mn) + 4(charge on O) = -1
(charge on Mn) + 4(-2) = -1
(charge on Mn) - 8 = -1
Charge on Mn = 7
The answer is C. 7
