Answer:
3.13cm/s²
Explanation:
Given
Initial velocity u = 3.5cm/s
Final velocity v = 8.2cm/s
Time t = 1.5secs
Required
Acceleration of the cart a
To get that, we will use the equation of motion
v = u+at
Substitute the given parameters
8.2 = 3.5+1.5a
1.5a = 8.2-3.5
1.5a = 4.7
a = 4.7/1.5
a = 3.13cm/s²
Hence the acceleration to the cart is 3.13cm/s²
Using the 3rd equation of motion:
= v² - u² = 2gs ------ [g = Acceleration due to gravity]
= v² - 20² = 2 × 10 × 300
= v² - 400 = 6000
= v² = 6000 - 400
= v = √5600
= v = 74.83 m/s
And yeah it's done :)
The distance between two consecutive points in a wave is called the wavelength.
Acceleration = (change in speed) / (time for the change)
Change in speed = (later speed) - (earlier speed) = (13 - 24) = -11 km/hr
Time for the change = 2 seconds
Acceleration = (-11 km/hr) / (2 sec)
Acceleration = -5.5 km/hr-sec (B)
Speed is the same as the initial: 25m/s.
*if* you need vectors though:
final velocity = (25*cos(35), -25*sin(35) ) m/s