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2 years ago

In the diagram below of triangle EFG, H is a midpoint of EF and J is a midpoint

Mathematics

1 answer:

cricket20 [7]2 years ago

5 0

try it on

https://www.wolframalpha.com it will helpp you for the math problem :)

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If a ladder is to be placed 3 feet from the side of a house. If top of the ladder rests exactly on the edge of the house when it

likoan [24]

Answer:

7 feet long

Step-by-step explanation:

This set up will give a right angle triangle where;

Length of the ladder is the hypotenuse = x

The distance of the ladder to the house is the adjacent = 3 feet

Angle of elevation theta = 72 degrees

Using the CAH in trigonometry identity;

cos theta = adjacent/hypotenuse

cos 72 = 3/hyp

hyp = 3/cos72

hyp = 3/0.4258

hyp = 7.05 feet

Hence the ladder is approximately 7 feet long

6 0

2 years ago

Please help ill mark brainliest!!

kompoz [17]

If sides are congruent then the angles ACROSS from them are also congruent.
Since WV and VU are congruent, angle U is congruent to angle W.
Set up an equation and solve.
See attachment.
x = 8
Angle w = 63

7 0

2 years ago

8n+2=18? Show Your Work.

Yuri [45]

18 - 2 = 16
8n = 16
Divide
N = 2

7 0

3 years ago

Read 2 more answers

In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=

just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}$ Given

$\displaystyle 2) \text{ } m \angle PAB = 60$ Definition of equilateral.

$3)\text{ } m \angle QAC = 60$ Definition of equilateral.

$4)\text{ } m\angle PAB = m\angle QAC$ Substitution

$5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC$ Angle Addition

$\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC$ Angle Addition

$7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC$ Substitution

$\displaystyle 8)\text{ } m\angle PAC=m\angle QAB$ Substitution

$9)\text{ } PA=BA$ Definition of equilateral

$10)\text{ } AC=AQ$ Definition of equilateral

$\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ$ Side-Angle-Side Congruence*

$\displaystyle 12)\text{ } PC=BQ$ CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0

2 years ago

Read 2 more answers

A line includes the points (8,-2) and (-8,-4). What is the slope intercept

VladimirAG [237]

Answer:

The equation of the line would be y = 1/8x - 3

Step-by-step explanation:

to find the slope intercept form of the line, you must first find the slope. You can do this using the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-2 - -4)/(8 - -8)

m = 2/16

m = 1/8

Then you can use this slope along with either point in point-slope form. Then solve for y.

y - y1 = m(x - x1)

y + 4 = 1/8(x + 8)

y + 4 = 1/8x + 1

y = 1/8x - 3

8 0

2 years ago