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Andre45 [30]
3 years ago
13

Pb3(po4)2 compound name

Chemistry
2 answers:
ch4aika [34]3 years ago
8 0

Answer:

Lead phosphate

Explanation:

Olegator [25]3 years ago
4 0

Answer:

Lead phosphate

Lead phosphate has the formula Pb3(PO4)2, and the accepted practice for writing the solubility reaction of a sparingly soluble compound that will dissociate into a cation and anion is shown.

Explanation:

pls give brainliest when you pls and i hope i helped!

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Which of the following definitions best fits the definition of an environmental factor of an organism's
Vaselesa [24]

Answer:

<u><em>B.)</em></u>

<u><em>An environmental factor is a characteristic of the environment that changes how an organism interacts with the environment</em></u>

Explanation:

Hope this helps:)

8 0
3 years ago
A sample of the inhalation anesthetic gas Halothane, in a 500-mL cylinder has a pressure of 2.3 atm at 0°C. What will be the pre
STALIN [3.7K]

Answer: 2.56atm

Explanation:

P1/T1=P2/T2

P1T2=P2T1

P2=P1T2/T1

P1=2.3atm

P2=?

T1=0+273=273k

T2=32+273=305k

P2=2.3*305/273

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8 0
4 years ago
Read 2 more answers
An element with 7 electrons and 8 neutrons has an atomic mass of?? <br> 7, 8, or 15??
Alik [6]

Answer: 15

Explanation:

To find the atomic mass, you add the number of protons and neutrons. The number of electrons is the same as the number of protons

8 0
3 years ago
A solution with a pH of 2 is (Choose) acidic than(as) a solution with a pH of 6.
Licemer1 [7]

Answer:

more acidic

Explanation:

The closer to 0 the more acidic a solution.

- Hope that helps! Please let me know if you need further explanation.

3 0
4 years ago
If you had excess chlorine, how many moles of aluminum chloride could be produced from 28.0 g of aluminum?
MaRussiya [10]

Answer:

1.04 moles of AlCl₃

Explanation:

Balanced Equation:  2Al°(s) + 3Cl₂(g) => 2AlCl₃(s)

Approach => convert given data (28 g Al°) to moles. The number of moles  AlCl₃ would equal the number of moles aluminum because coefficients for Aluminum and Aluminum Chloride are equal.

moles Al° = (28g)/(27g/mole ) = 1.04 mole Al°

From balanced equation moles AlCl₃ produced equals moles of Al° produced = 1.04 mole AlCl₃ because coefficients of Al° & AlCl₃.

5 0
4 years ago
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