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2 years ago

12

There are several ways to model a compound. One type of model is shown. What is the chemical formula for the molecule modeled? О

СНО O CAH102 O C6H1202 O C6H90 | НО H H-C-H H H-C-C-C-C-O-H Η | Η H-C-H H
what is the chemical formula for the molecule modeled ?

1 answer:

stira [4]2 years ago

8 0

Answer:

It's most likely CAH102, if not i'm sorry

Explanation:

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falling objects drop with an average acceleration of 9.8m/sec/sec. if an object falls from a tall building how long will it take

sveta [45]

Answer:

5 seconds

Explanation:

<em>Acceleration = (final velocity - initial velocity) ÷ time</em>

<em> $a = \frac{v - u}{t}$ </em>

<em> $9.8 = \frac{49 - 0}{t}$ </em>

<em> $9.8 = \frac{49}{t}$ </em>

<em> $9.8t = 49$ </em>

<em> $t = \frac{49}{9.8}$ </em>

<em> $t = 5$ </em>

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2 years ago

A baseball with a mass of 0.3kg is thrown into the air with a speed of 50 m/s and is at a height of 10m above. What is the speed

makkiz [27]

a una velocidad de

22 m/s, quien lo golpea y devuelve en la misma

dirección con una velocidad de 14 m/s. Si el

tiempo de contacto del balón con la jugadora es

de 0,03 s, ¿con qué fuerza golpeó la jugadora el

balón?

21 Una bala de 0,8 g, está en la recámara de un rifl e

cuando se g

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3 years ago

Assume that the home construction industry is perfectly competitive and in long-run competitive equilibrium. It follows that: A.

olga nikolaevna [1]

Answer:

B. Marginal cost equals long-run average total cost.

Explanation:

The zero profit condition implies that entry continues until all firms are producing at minimum long run average total cost. Since the marginal cost curve cuts the long run average total cost curve at its minimum point, marginal cost and long run average total cost must be equal in long run equilibrium.

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3 years ago

Consider the following distribution of objects: a 2.00-kg object with its center of gravity at (0, 0) m, a 2.20-kg object at (0,

adelina 88 [10]

Answer:

body position 4 is (-1,133, -1.83)

Explanation:

The concept of center of gravity is of great importance since in this all external forces are considered applied, it is defined by

x_cm = 1 /M ∑ $x_{i}$ m_{i}

y_cm = 1 /M ∑ y_{i} mi

Where M is the total mass of the body, mi is the mass of each element

give us the mass and position of this masses

body 1

m1 = 2.00 ka

x1 = 0 me

y1 = 0 me

body 2

m2 = 2.20 kg

x2 = 0m

y2 = 5 m

body 3

m3 = 3.4 kg

x3 = 2.00 m

y3 = 0

body 4

m4 = 6 kg

x4=?

y4=?

mass center position

x_cm = 0

y_cm = 0

let's apply to the equations of the initial part

X axis

M = 2.00 + 2.20 + 3.40

M = 7.6 kg

0 = 1 / 7.6 (2 0 + 2.2 0 + 3.4 2 + 6 x4)

x4 = -6.8 / 6

x4 = -1,133 m

Axis y

0 = 1 / 7.6 (2 0 + 2.20 5 +3.4 0 + 6 y4)

y4 = -11/6

y4 = -1.83 m

body position 4 is (-1,133, -1.83)

7 0

3 years ago

Estimate how long it took King Kong to fall straight down from the top of the Empire State Building (380 m high). Express your a

ankoles [38]

Answer:

It will take 8.80 sec to fall from the building

Explanation:

We have given height pf the state building h = 380 m

Initial velocity will be 0 m /sec

So u = 0 m/sec

Acceleration due to gravity $g=9.8m/sec^2$

We have to find the fall time

According to second equation of motion $h=ut+\frac{1}{2}gt^2$

So $380=0\times t+\frac{1}{2}\times 9.8\times t^2$

$t^2=77.55$

t = 8.80 sec

3 0

2 years ago