you will need to use the law of cosines since this picture does not indicate that this is a right triangle
c^2 = a^2 + b^2 – 2ab cos C,
16^2 = 17^2+8^2 -2*17*8*cosC
256=289-272cosC
-33=-272cosC
33/272 = cosC
cos^-1 (33/272)=C taking the inverse cos
C=83.0 (to the nearest tenth)
b^2 = a^2 + c^2 – 2ac cos B,
8^2 = 17^2 +16^2 -2*17*16cosB
64=289-544cosB
-225=-544cosB
225/544=cosB
cos^(-1) =B
B=65.5
A=180-83-65.6
A=31.4
Answer: 300
Step-by-step explanation: you first multiply 5 and 6 that is 30. Then you multiply the product by 100 that is 300
1) y= -5
2) m = -1
3) k = 3
4) y = -5
Step-by-step explanation:
1) 
Solving:
2) ![8(-1+m)+3 = 2 [m-5 1/2]\\](https://tex.z-dn.net/?f=8%28-1%2Bm%29%2B3%20%3D%202%20%5Bm-5%201%2F2%5D%5C%5C)
Solving:
![8(-1+m)+3 = 2 [m-5 \frac{1}{2} ]\\-8+8m+3=2 [m-\frac{11}{2} ]\\8m-5=2 [\frac{2m-11}{2} ]\\8m-5=2m-11\\Combining\,\,like\,\,terms:\\8m-2m=-11+5\\6m=-6\\m=-6/6\\m=-1](https://tex.z-dn.net/?f=8%28-1%2Bm%29%2B3%20%3D%202%20%5Bm-5%20%5Cfrac%7B1%7D%7B2%7D%20%5D%5C%5C-8%2B8m%2B3%3D2%20%5Bm-%5Cfrac%7B11%7D%7B2%7D%20%5D%5C%5C8m-5%3D2%20%5B%5Cfrac%7B2m-11%7D%7B2%7D%20%5D%5C%5C8m-5%3D2m-11%5C%5CCombining%5C%2C%5C%2Clike%5C%2C%5C%2Cterms%3A%5C%5C8m-2m%3D-11%2B5%5C%5C6m%3D-6%5C%5Cm%3D-6%2F6%5C%5Cm%3D-1)
3) 
(Note: Considering 8(12-k)=3(k+21) instead of 8(12-k)=3(k=k+21))
Solving:
4) 
Solving:
Keywords: Solve for variables.
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