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REY [17]
3 years ago
13

Which type of light causes damage to plants? (Choose one) >_<

Chemistry
2 answers:
Annette [7]3 years ago
6 0

the answer is ultraviolet

Vesnalui [34]3 years ago
5 0

Answer:

microwave

Explanation:

your gonna have one crispy plant if you put it in the microwave XD

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Carbon dioxide is a...
Marina86 [1]

Answer: Option B) Pure Substance &

Compound

Explanation:

Carbon dioxide is a compound because it is formed when one carbon atom and two oxygen atoms chemically combined together.

C(s) + O2(g) ---> CO2(g)

Also, CO2 is a pure substance because it is natural and cannot be broken down easily or separated by physical methods.

5 0
3 years ago
What are the advantages and disadvantages of living in a group?
Feliz [49]
Advantages
people are there to help
never lonely
they could do things for you

disadvantages
loud
annoying to you
they don't do work
3 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
4 years ago
Is the following detente true or false? Paramecia have two nuclei
blondinia [14]
Paramecia have a micro nuclei and a macro nuclei.
6 0
3 years ago
Provide the nuclear equation for a decay of polonium-214
s344n2d4d5 [400]
The nuclear equation that describes the alpha decay of Polonium-210 can be written like this:
210/
84Po→206/82Pb+4/2 He
3 0
3 years ago
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