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3 years ago

What conditions would probably exist the dew point and dry bulb temperatures to be the same at the ground ?

1 answer:

4 0

Answer: The conditions would probably exist the drew point and dry bulb temperatures to be the same at the ground because When the dew point temperature and air temperature are equal, the air is said to be saturated. Dew point temperature is NEVER GREATER than the air temperature. Therefore, if the air cools, moisture must be removed from the air and this is accomplished through condensation.

Explanation:

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____ crust forms the ocean floors

Fittoniya [83]

Answer:

lithosphere

Explanation:

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3 years ago

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Which of the following statements best describes the method of energy conservation known as cogeneration?

Mazyrski [523]

Answer:

heat and power

Explanation:

is the simultaneous production of electricity and heat both of which are used

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3 years ago

Which term is defined as the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through

KATRIN_1 [288]

Answer:

Index of refraction

Explanation:

or refractive index

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3 years ago

The mass of a proton is 1833 times larger than the mass of an electron. When a proton an electron interact with each other the o

Ad libitum [116K]

B. Exactly the same as the electric force of the electron on the proton.

<u>Explanation:</u>

Even if the mass of proton is increased or decreased, the force between electron and proton will remain the same because force is dependent on the charge of the object and distance between them. The force between the charges is independent of their masses. So, even if the mass of a proton is 1833 times larger than the mass of an electron, the force between them will be same.

According to Coulomb's law:

$F = k\frac{q_1q_2}{r^2}$

where,

F is the force

q₁ and q₂ are the charges

r is the distance between the charges

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3 years ago

Consider a positive charge Q and a point B twice as far away from Q as point A. What is the ratio of the electric field strength

Vikentia [17]

Answer:

$\frac{E_{A}}{E_{B}}=4$

Explanation:

The electric field is defined as the electric force per unit of charge, this is:

$E=\frac{F}{q}$ .

The electric force can be obtained through Coulomb's law, which states that the electric force between to electrically charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges. The electric force can be expressed as

$F=\frac{kQq}{r^{2}}$ .

By substitution we get that

$E=\frac{kQq}{qr^{2}}\\\\E=\frac{kQ}{r^{2}}$

Now, letting $E_{A}$ be the electric field at point A, letting $E_{B}$ be the electric field at point B, and letting R be the distance from the charge to A:

$E_{A}=\frac{kQ}{R^{2}}\\\\E_{B}=\frac{kQ}{(2R)^{2}}$ .

The ration of the electric fields is

$\frac{E_{A}}{E_{B}}=\frac{\frac{kQ}{R^{2}}}{\frac{kQ}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(4)R^{2}}}\\\\\\\frac{E_{A}}{E_{B}}=\frac{1}{\frac{1}{(4)}}\\\\\frac{E_{A}}{E_{B}}=4$

This means that at half the distance, the electric field is four times stronger.

4 0

3 years ago