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3 years ago

TIMED EXAM URGENT

Chemistry

2 answers:

vlabodo [156]3 years ago

5 0

Answer:

2 s 3 s

Explanation:

Coz they on the spdf

Sergio [31]3 years ago

4 0

2s and 3s because s orbitals have a spherical shape which means they have the same shape

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Radioactive cobalt-60 is frequently used in treating cancer. It took 24 years for a 10 gram sample to decay to 0.625 grams. What

-BARSIC- [3]

Answer:

Half life is 6 years.

Explanation:

T½ = In2 / λ

Where λ = decay constant.

But N = No * e^-λt

Where N = final mass after a certain period of time

No = initial mass

T = time

N = 0.625g

No = 10g

t = 24 years

N = No* e^-λt

N / No = e^-λt

λ = -( 1 / t) In N / No (inverse of e is In. Check logarithmic rules)

λ = -(1 / 24) * In (0.625/10)

λ = -0.04167 * In(0.0625)

λ = -0.04167 * (-2.77)

λ = 0.1154

T½ = In2 / λ

T½ = 0.693 / 0.1154

T½ = 6.00 years.

The half life of radioactive cobalt-60 is 6 years

5 0

3 years ago

Which of the following represents an organic compound?

bixtya [17]

Answer:

third one

Explanation:

h\ /h

c=c

h/ \h

6 0

3 years ago

Read 2 more answers

Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen

alexgriva [62]

Answer:

$V_{base}=24.04mL$

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

$2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O$

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

$2M_{base}V_{base}=M_{acid}V_{acid}$

Therefore, for is to compute the volume of the used base, we proceed as shown below:

$V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}$

And we plug in to obtain:

$V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL$

Best regards!

8 0

3 years ago

One mL of water is equal to

solniwko [45]

1 milliliter of water (ml)

Equals : 0.04 ounces of water (oz wt.)

Fraction : 1/25 ounces of water (oz wt.)

3 0

3 years ago

A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri

Helga [31]

The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
$F= \frac{m* v^{2} }{r}$
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if <span> $F= \frac{m* v^{2} }{r}$ , then:
</span> $r= \frac{3* v^{2} }{F}$
⇒ $r = \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }$
⇒ $r= \frac{1200*400*kg*m^{2}*s^{2} }{6000kg*m/s^{2} }$
⇒ $r= \frac{480,000m}{6000}$
⇒ $r=80m$

6 0

3 years ago