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3 years ago

Limit question thing plz help me

Mathematics

1 answer:

Sphinxa [80]3 years ago

5 0

Answer:

The limit does not exist

Step-by-step explanation

For this question you have to look at the function and see what y value does it approach as it gets closer and closer to x =2, from the left side it looks like it approaces 4 and from the left side it looks like it's approaching 1, since the limits from the left and right sides are not the same, the limit does not exist

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Step-by-step explanation:

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shutvik [7]

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3 years ago

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Mary ran 4 miles in 37 minutes. If she continued at the same pace, how long would it take her to run 11 miles?

Pavlova-9 [17]

Solution:

we are given that

Mary ran 4 miles in 37 minutes.

we have been asked to find

how long would it take her to run 11 miles?

Since Mary ran 4 miles in 37 minutes, it mean time taken to run 1 miles can be given by

$t_{1 \ mile}=\frac{37}{4} \ minutes.$

Hence we can write , time taken in running 11 miles as

$t_{11 \ mile}=\frac{37}{4}*11 \ minutes.\\ \\ t_{11 \ mile}=\frac{407}{4} \ minutes\\ \\ t_{11 \ mile}=101.75 \ minutes\\$

6 0

3 years ago

Simplify (y + 1)^5y + 1)^3

kondor19780726 [428]

Note: Your expression sounds a little unclear, so I am assuming your expression is

$\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3$

But, the procedure to solve the expressions involving exponents remains the same, so whatever the expression is, you may be able to get your concept clear.

In the end, I will solve both expressions.

Answer:

Please check the explanation

Step-by-step explanation:

Given the expression

$\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3$

solving the expression

$\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}$