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Kitty [74]
2 years ago
13

How many kilojoules are needed to convert 77.5 grams of ice at -8.00°C to water at 95.0°C?

Chemistry
1 answer:
Over [174]2 years ago
7 0
Q=mcθ
m= 0.0775 kg
c= 4184 J·kg−1·K−1.
θ= T(final) - T(initial), 95-(-8)

Q=33398.78 J so kJ divide 1000

= 33.39878 kJ
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Iron is extracted from its ore (hematite) in the blast furnace. Which gas is produced as a waste product?
Diano4ka-milaya [45]

Answer:

CO2

Explanation:

CO2 or carbon dioxide is produced when iron is extracted from its ore. Carbon monoxide Co is used as reducing agent in iron extraction. In this reaction iron ore is reduced to iron and CO is oxidized to CO2 or carbon dioxide which is released in the process. There extraction of iron is redox reaction.

4 0
3 years ago
Place where food is stored and partially digested
Ostrovityanka [42]
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3 years ago
What is the total pressure in units of kPa in a 7.85 L container that contains 4.45 moles of N2 and 2.45 moles of O2 at a temper
dem82 [27]

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32.42

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7 0
2 years ago
The combustion of 1 mole of CO according to the reaction CO(g) + ½O2(g) → CO2(g) + 67.6 kcal gives off how much heat?
Tomtit [17]
When the enthalpy value is given, we can calculate how much heat is use or produces in a given equation. 

67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction=  1 mol of CO (based on the coefficient)

so 1 mole of CO gives us 67.6 kCal of heat.

calculation:

1 mol CO\frac{67.5 kcal}{1 mol CO} = 67.5 kcal




5 0
2 years ago
zn (s) 2 hcl (aq) -----> zncl2 (aq) h2(g) if 520 ml of h2 is collected over water at 28oc and the atmospheric pressure is 1.0
nadya68 [22]

The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.

Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.

We recognise that

h * 2 = PT - P * h * 20 = 1atm - 0.037atm

= 0.963 atm

1 * h * 2 = Ph * 2V / R * T

= 0.963 atm x 0.520 L / 0.0821 L atm/

molK * 301

= 0.02 mol h2

= 0.02molZn

So 0.02 mol Zn x 65.39 g/mol

= 1.33 g Zn

Read more about zinc;

brainly.com/question/28880469

#SPJ4

3 0
1 year ago
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