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3 years ago

How many kilojoules are needed to convert 77.5 grams of ice at -8.00°C to water at 95.0°C?

1 answer:

Over [174]3 years ago

7 0

Q=mcθ
m= 0.0775 kg
c= 4184 J·kg−1·K−1.
θ= T(final) - T(initial), 95-(-8)

Q=33398.78 J so kJ divide 1000

= 33.39878 kJ

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