How many moles are in 230 grams of calcium phosphate
2 answers:
Answer: 0.74 moles
Explanation:
The first step is to figure out the chemical formula for calcium phosphate. Since we know that calcium is a metal, this will be an ionic bond. Calcium is written as Ca and has a charge of +2. Phosphate is written as PO4 with a charge of -3. To come up with the subscripts for this formula, cross the charges. That means that you will get .
Next, calculate how many grams one molecule of calcium is. Calcium has an atomic weight of 40, and there are 3 molecules of calcium, so 40 x 3 = 120. Phosphorus has an atomic weight of 31, and there are 2 molecules of phosphorus, so 31 x 2 = 62. Oxygen has an atomic weight of 16, and there are 8 molecules of oxygen, so 16 x 8 = 128. Adding all of those together gives you 310 g.
Now, using stoichiometry, we can figure out the question. We know that there are 230 grams. We also know that one mole weighs 310 g. If you divide 230 by 310, you will get your answer, which is 0.74 moles.
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Answer:
215.12 g
Explanation:
The change in the bolling temperature is a collateral property called ebullioscopy. The elevation on temperature occurs because there'll be a solute in the pure compound, and that solute(generally non-volatile) has a different boiling point, so the total bolling pint should increase.
To calculate the elevation in the temperature, we must use the Raoult equation:
ΔT = KbxWxi
Where <em>ΔT</em> is the variation of the temperature of boiling point, <em>Kb</em> is the
ebullioscopy constant, <em>W</em> is the molarity, and <em>i</em> the Vant' Hoff factor, which for molecules is also equal to 1, because they don't form ions. So:
82.00 - 78.40 = 1.22xW
W = 3.60/1.22
W = 2.9508
The molarity can also be calculated by:
Where <em>m1</em> is the mass of the solute (in grames), <em>M1</em> is the molar mass of the solute, and <em>m2</em> is the mass of the solvent (in kg).
The density of ethanol is 0.789 g/cm³, and 1 mL = 1 cm³, so 600.00 mL = 600.00 cm³ :
0.789 = m2/600
m2 = 473.4 g = 0.4734 kg
The molar mass of geraniol is:
C: 12 g/mol x 10 = 120 g/mol
H: 1 g/mol x 18 = 18 g/mol
O: 16 g/mol x 1 = 16 g/mol
M1 = 154 g/mol
Then:
m1 = 215.12 g of geraniol.
Answer:
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.
The given balanced equilibrium reaction is:
The expression for equilibrium constant for this reaction will be,
Thus the equilibrium constant expression for this reaction is